Perform the indicated multiplication:
<span>7p-(3p+4)= -2(2p-1) + 10
becomes
7p - 3p - 4 = -4p + 2 + 10
Group like terms:
7p - 3p + 4p = 2 + 10 + 4
8p = 16 => p = 2 (answer)</span>
The balloon is in the air for 3sThe max height is 44mThe max height occurs at x=0
You can add 9+1 then make ten and add 10 +1
to find the distance between 2 points we should apply the formula
![d=\sqrt[]{(x_2-x_1)^2+(y_2-_{}y_1)^2_{}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-_%7B%7Dy_1%29%5E2_%7B%7D%7D)
call point q as point 1 for reference in the formula and p as point 2
replace the coordinates in the formula
![d=\sqrt[]{(3-(-1))^2+(-4-(-1))^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%5B%5D%7B%283-%28-1%29%29%5E2%2B%28-4-%28-1%29%29%5E2%7D)
simplify the equation
![\begin{gathered} d=\sqrt[]{(3+1)^2+(-4+1)^2} \\ d=\sqrt[]{4^2+(-3)^2} \\ d=\sqrt[]{16+9} \\ d=\sqrt[]{25} \\ d=5 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20d%3D%5Csqrt%5B%5D%7B%283%2B1%29%5E2%2B%28-4%2B1%29%5E2%7D%20%5C%5C%20d%3D%5Csqrt%5B%5D%7B4%5E2%2B%28-3%29%5E2%7D%20%5C%5C%20d%3D%5Csqrt%5B%5D%7B16%2B9%7D%20%5C%5C%20d%3D%5Csqrt%5B%5D%7B25%7D%20%5C%5C%20d%3D5%20%5Cend%7Bgathered%7D)
the distance between the 2 points is 5 units
Answer:
p>3
Step-by-step explanation:
<=> 3p - 9 - 5p > -3p - 6
<=> -2p + 3p > -6 + 9
<=> p > 3
