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Colt1911 [192]
3 years ago
9

Find AB. Round to the nearest tenth. 61°

Mathematics
2 answers:
alekssr [168]3 years ago
8 0
AB~ 14.3 i believe but Im not sure
anzhelika [568]3 years ago
6 0

Answer:

AB ≈ 14.3

Step-by-step explanation:

We're given <em>two sides </em>(BC and CA) and an <em>angle </em>(C)<em> between them</em>; the <em>law of cosines </em>is a good tool for calculating the third side of the triangle here. To remind you, the law of cosines tells us the relationship between the sides of a triangle with side lengths a, b, and c:

c^2=a^2+b^2-2ab\cos{C}

Where C is the angle between sides a and b. c is typically the side we're trying to find, so on our triangle, we have

c=AB\\a=BC=16\\b=CA=5\\C=m\angle C=61^{\circ}

Substituting these values into the law of cosines:

c^2=16^2+5^2-2(16)(5)\cos{61^{\circ}}\\c^2=256+25-160\cos{61^{\circ}}\\c^2=281-160\cos{61^{\circ}}\\c=\sqrt{281-160\cos{61^{\circ}}}\\c\approx 14.3

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