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natali 33 [55]
3 years ago
12

At a zoo, the lion pen has a ring-shaped sidewalk around it. The other edge of the sidewalk is a circle with a radius of 11 m. T

he inner edge of the sidewalk is a circle with a radius of 9m. (A) write and simplify an expression for the extra area of the sidewalk. (B) find the approximate area of the sidewalk. Use 3.14 to approximate J,L.
Mathematics
1 answer:
Vikentia [17]3 years ago
5 0
Diameter = 2r
6 = 2r r = 3 for the radius of the flowerbed
If we were to include the sidewalk around the bed, the diameter would stretch out another meter in both directions, meaning adding 2 meters to the diameter making the new diameter 6 + 2 = 8 and 8/2 = 4 so 4 = radius of the circle including the sidewalk. Find the area of the big circle and subtract the area of the smaller circle to find the area of the sidewalk.
Small circle = pi*3 squared.
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Jose needs 6.2 lb of organic blueberries to make smoothies. Organic blueberries are on sale for $2.85 per pound. Jose estimates
guajiro [1.7K]

Answer:

Jose incorrectly rounded $2.85 down to $2. The estimate should be $18.

Step-by-step explanation:

When we round 6.2 lb to the nearest pound we round down, because the digit after point is less than 5 (2<5), so

6.2\ lb\approx 6\ lb

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\$2.85\approx \$3

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3 years ago
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Use the Polygon tool to draw the image of the given quadrilateral under a dilation with a scale
Nataly [62]

Answer: See the picture attached.

Step-by-step explanation:

A Dilation is defined as  a transformation in which the image and the pre-image have the same shape, but their sizes are different.

When the scale factor is greater than 1, the image obtained after the  dilation is greater than the pre-image and it is an "Enlargement".

When the scale factor is is between 0 and 1,  the image obtained after the  dilation is smaller than the pre-image and it is an "Reduction".

In this case we know that the scale factor is:

scale\ factor=\frac{2}{3}

Since:

0

It is a Reduction.

You can identify that the vertices of the quadritaleral are:

(-3,0),(-9,-3),(-6,-9),(3,-6)

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Then, you get:

(\frac{(-3)(2)}{3},0*\frac{2}{3})=(-2,0)\\\\(\frac{(-9)(2)}{3}),\frac{(-3)(2)}{3})=(-6,-2)\\\\(\frac{(-6)(2)}{3},\frac{(-9)(2)}{3})=(-4,-6)\\\\(3*\frac{2}{3},\frac{(-6)(2)}{3})=(2,-4)

Now you can plot the points and draw the image of the given quadrilateral.

See the picture attached.

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Answer:

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Step-by-step explanation:

step by step

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