<em>Lets say that √(3+i) is the magnitude of your vector. In polar form, i represents the x component and j represents the y component of the vector. Therefore, the polar form is icosθ√(3+i) + jsinθ√(3+i)</em>
draw a diagram :
<em>z = r(cos θ + i sin θ), where z = complex number, r = modulus, θ = angle of rotation For the given:r = 2θ = π/6 √3 + i = 2(cos π/6 + i sin π/6)</em>
<em>hope</em><em> </em><em>thz</em><em> </em><em>hlpz</em><em> </em><em>✿</em>
Ok so to answer this, we first need to figure out the area of both circles
we will use the formula A=πr²
so our two areas end up being 121π and 81π
now all we do is subtract the smaller from the larger
121π - 81π = 40π
shaded region = 40π
Answer:
operator
Step-by-step explanation:
Operator is represented as any symbol that indicates an operation to be performed.
Examples:
- Square root of√x, which indicates the square root is to be taken
- d/dx, which indicates differentiation with respect to x is to be performed
