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saveliy_v [14]
3 years ago
5

A can of vegetables has radius 1.8 in and height 5.9 in. Find the volume of the can. use 3.14 for pi​

Mathematics
2 answers:
Leya [2.2K]3 years ago
8 0
Answer 60.1 or 60in3
nalin [4]3 years ago
5 0

Answer:

The volume of cyclinder is 60 in³

Step-by-step explanation:

Using the formula of the volume of cyclinder, V = π×r²×h, where r is the radius and h is the height. Then you are able to find it by substituing the following value into the formula :

π = 3.14

r = 1.8 in

h = 5.9 in

V = 3.14×1.8²×5.9

= 60.0 in³ (3s.f)

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Carrie needs to determine the number of tiles that will fit in each row along the back of the shower. If the back of the shower
SVEN [57.7K]
You need to add the dimensions
8 0
3 years ago
If a1=10 and an=an-1+4 then find the value of a5
tamaranim1 [39]

Answer:

26

Step-by-step explanation:

Each term is the previous with 4 added to it.

a1 = 10, a2 = 14, a3 = 18, a4 = 22, a5 = 26

3 0
3 years ago
Lots of 40 components each are deemed unacceptable if they contain 3 or more defectives. The procedure for sampling a lot is to
MrRissso [65]

Answer:

The probability of founding exactly one defective item in the sample is P=0.275.

The mean and variance of defective components in the sample are:

\mu=0.375\\\\\sigma^2=0.347

Step-by-step explanation:

In the case we have a lot with 3 defectives components, the proportion of defectives is:

p=3/40=0.075

a) The number of defectives components in the 5-components sample will follow a binomial distribution B(5,0.075).

The probability of having one defective in the sample is:

P(k=5)=\binom{5}{1}p^1(1-p)^4=5*0.075*0.925^4=0.275

b) The mean and variance of defective components in the sample is:

\mu=np=5*0.075=0.375\\\\\sigma^2=npq=5*0.075*0.925=0.347

The Chebyschev's inequality established:

P(|X-\mu|\geq k\sigma)\leq \frac{1}{k^2}

6 0
3 years ago
I need help with this please. :)
stepladder [879]

Answer:

64x³+4

-------------

2x-1

Step-by-step explanation:

I hope this helps. :)

3 0
3 years ago
Which equation, when graphed, has x-intercepts at (-1,0) and (-5,0) and a y-intercept at (0, -30)?
Vladimir [108]

If a function has roots -1 and -5, it must be in the form

f(x)=a(x+1)(x+5)

We can fix the coefficient a by imposing the passing through (0,-30):

f(0)=-30=a(1)(5)\iff a=-6

So, the function is

f(x)=-6(x+1)(x+5)

7 0
3 years ago
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