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2 years ago

Find the area the figure is not drawn to scale 6.9 cm 4 cm

Mathematics

1 answer:

Grace [21]2 years ago

4 0

Please check attached file to see if you mean the same triangle.

Basically, to find the area of a triangle, you are going to use the formula :
A = b × h where b is base, h is height.
2

others also use the formula: Area=1/2(bxh)

Based on the figure, we have 6.9 cm (base) and 4 cm (height) as given.
Let us work out on the area of the said triangle.
A= 6.9cm × 4cm
2

= 27.6cm²
 2
A= 13.8 cm²

Hope this helps!

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2 years ago

What are the next three terms of the sequence below?

vichka [17]

Answer:

64, 256, 1024 (D)

Step-by-step Explanation:

The sequence is following some rule. And the rule is: Multiplying the term with 4 to get the next term. Like:

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2 years ago

Read 2 more answers

Find the value of each variable

aniked [119]

Answer:

Answer d)

$a= 10*\sqrt{3}$ $b=5*\sqrt{3}$ , $c=15$ , and $d=5$

Step-by-step explanation:

Notice that there are basically two right angle triangles to examine: a smaller one in size on the right and a larger one on the left, and both share side "b".

So we proceed to find the value of "b" by noticing that it the side "opposite side to angle 60 degrees" in the triangle of the right (the one with hypotenuse = 10). So we can use the sine function to find its value:

$b=10*sin(60^o)= 10*\frac{\sqrt{3} }{2} = 5*\sqrt{3}$

where we use the fact that the sine of 60 degrees can be written as: $\frac{\sqrt{3} }{2}$

We can also find the value of "d" in that same small triangle, using the cosine function of 60 degrees:

$d=10*cos(60^o)=10* \frac{1}{2} = 5$

In order to find the value of side "a", we use the right angle triangle on the left, noticing that "a" s the hypotenuse of that triangle, and our (now known) side "b" is the opposite to the 30 degree angle. We use here the definition of sine of an angle as the quotient between the opposite side and the hypotenuse:

$sin(30^o)= \frac{b}{a} \\a=\frac{b}{sin(30)} \\a=\frac{5*\sqrt{3} }{\frac{1}{2} } \\a= 10*\sqrt{3}$

where we used the value of the sine function of 30 degrees as one half: $\frac{1}{2}$

Finally, we can find the value of the fourth unknown: "c", by using the cos of 30 degrees and the now known value of the hypotenuse in that left triangle:

$c=10*\sqrt{3} * cos(30^o)=10*\sqrt{3} *\frac{\sqrt{3} }{2} \\c= 5*3=15$