I would say the correct answer would be light travels faster in medium 3 then medium 2.
Answer:
1.5x10^-4C
C=Couloumb's
Explanation:
Expression for the electric force between the two charges is given by -
F = (k*q1*q2) / r^2
Here, k = constant = 9 x 10^9 N*m^2 / C^2
F=25N
q1 = 1.9x10^-6 x 10^-6 C
q2 = ?
r = 0.32m
Substitute the given values in the above expression -
25N= 9x10^9 *1.9x10^-6 *q2 / 0.32m^2
25N= 17,100*q2 / 0.1024m
Next part is algebra multiply both sides by 0.1024 to remove denominator
2.56=17,100*q2
Divide both sides to isolate q2
q2= 1.5x10^-4C
Answer:
The speed of the combined vehicles is 6.82m/s
Explanation:
Using the law of conservation of momentum which stayed that the sum of momentum of bodies before collision is equal to their sum of momentum after collision. After collision, both object moves with the same velocity.
Momentum = mass×velocity
Before collision:
Momentum of vehicle or mass 3000kg moving with velocity 25m/s
= 3000×25
= 75000kgm/s
Pa = 75000kgm/s
Momentum of vehicle with mass 2500kg moving with velocity of -15m/s
= 2500×-15
= -37500kgm/s
After collision:
Momentum = (3000+2500)V
Where v is their common velocity
Momentum after collision = 5500V
Based on the law:
75000+(-37500) = 5500V
75000-37500 = 5500V
37500 = 5500V
V = 37500/5500
V = 6.82m/s
Answer:
As one goes "forward" in time, the second law of thermodynamics says, the entropy of an isolated system can increase, but not decrease. ... Thus, entropy measurement is a way of distinguishing the past from the future.
Explanation:
