Answer:
v₀ = 9,798 ft / s
Explanation:
We can solve this problem with kinematics in one dimension, when the train stops the speed is zero, the acceleration is negative so that the train stops. Let's use the equation
v² = v₀² - 2 a d
v = 0
v₀ = √2 a d
In the problem it indicates that the acceleration is g / 2, we substitute
v₀ = √2 (g / 2) d
Let's calculate
v₀ = √ 2 32/2 3 = √32 3
v₀ = 9,798 ft / s
-Geographic north and south poles are determined by the earth's spin.
-Magnetic north and south is determined by the direction a compass points.
Hope this helps,
kwrob
Answer:
Hey mate I shall not tell you the answer I shall explain it to you after this if still you can't understand then say
Explanation:
Derive v = u + at by Graphical Method. Consider the velocity – time graph of a body shown in the below Figure
Derive s = ut + (1/2) at2 by Graphical Method. Velocity so time graph to derive the equations of motion.
Derive v2 = u2 + 2as by Graphical Method. Velocity–Time graph to derive the equations of motion.
I hope you understand now
enjoy your day
#Captainpower :)❤❤
Answer:
<em>1,378.9ms²</em>
Explanation:
Given the following
Distance S = 70.6m
Time t = 0.32secs
Initial velocity = 0m/s
Required
Acceleration
Using the equation of motion
S = ut+1/2at²
Substitute
70.6 = 0+1/2a(0.32)²
70.6 = 0.0512a
a = 70.6/0.0512
a = 1,378.9
<em>Hence the acceleration is 1,378.9ms²</em>