two vehicles have a head on collision. one vehicle has a mass of 3000 kg and moves at 25 m/s while the second vehicle has a mass
1 answer:
You might be interested in
Answer:
θ '= 4975 rev
Explanation:
For this exercise let's use the relationship between work and the change in kinetic energy
W = ΔK
the expression for work is
W = - τ Δθ
where the negative sign indicates that the torque is in the opposite direction to rotation
kinetic energy
K = ½ I w²
we substitute
- τ Δθ = 0 - ½ I w²
θ =
if we approach the rotor to a cylinder with an axis of rotation through its center
I = ½ m r²
we substitute
θ = ½ (½ m r²)
How the measurements are in the English system, the weight
W = m g
m = W / g
let's reduce to the english system
w = 3600 rev / min (2pi rad / 1rev) (1 min / 60s) = 376.99 rad / s
r = 9 in (1 ft / 12in) = 0.75 ft
let's calculate
m = 125/32 = 3.91 slug
θ = ¼ 3.91 0.75² 376.99² / 2.5
θ = 3.126 10⁴ rad
let's reduce to revolutions
θ’= 3.126 10⁴ rad (1rev / 2π rad)
θ’= 4974.9 rev
θ '= 4975 rev
a) The mirror's radius of curvature will be 2.7 cm
B) The magnification of the image will be 4.0.
<h3>What is a concave mirror?</h3>When a hollow spherical is divided into pieces and the exterior surface of each cut portion is painted, it forms a mirror, with the inner surface reflecting the light.
From the mirror equation;
Hence,
The radius of curvature is twice of the focal length;
Hence, the mirror's radius of curvature will be 2.7 cm.
The magnification factor is found as;
Hence, the magnification of the image will be 4.0.
To learn more about the concave mirror, refer to the link;
#SPJ1
Answer:
11.25m
Explanation:
Given parameters:
Initial velocity = 0m/s
Time of running = 3s
Acceleration = 2.5m/s²
Unknown:
Displacement = ?
Solution:
To solve this problem, we apply one of the motion equations.
S = ut + at²
u is the initial velocity
t is the time taken
a is the acceleration
S = (0 x 3) + ( x 2.5 x 3²) = 11.25m