Answer and Explanation:
A function is said to be increasing, if the derivative of function is f’(x) > 0 on each point. A function is said to be decreasing if f”(x) < 0.
Let y = v (z) be differentiable on the interval (a, b). If two points z1 and z2 belongs to the interval (a, b) such that z1 < z2, then v (z1) ≤ v (z2), the function is increasing in this interval.
Similarly, the function y = v(z) is said to be decreasing, when it is differentiable on the interval (a , b).
Two points z1 and z2 Є (a, b) such that z1 > z2, then v (z1) ≥ v(z2). The function is decreasing on this interval.
The function y = v (z)
The derivative of function Y’ = v’(z) is positive, then the function is increasing.
The function y = v (z)
The derivative of function y’ is negative, then the function is decreasing.
Answer:
6.21 is the radius I believe
Step-by-step explanation:
Answer:
Step-by-step explanation:
[pay attention to the signs :)
Solve the equation for y using the formula for slope: y + mx + b
2x^2 + 5y^2 = 14
5y^2 = -2x^2 + 14
y^2 = -2/5x^2 + 14/5
y = the sq root of -2x^2/5 + 14/5
There is no integer solution to the square root of a negative number.
Answer:
This question cannot be solved.
Step-by-step explanation:
It has more than one equal sign; there is no way to compute this.
