Answer:
19
Step-by-step explanation:
1st you will use a^2+b^2=c^2
next you plug them in so it would be a^2+16^2=25^2
next you would solve it to a^2+256=625
then you would get 369 and square root it
and your answer will be 19.2.
Answer:
r = sqrt(16/pi)
Step-by-step explanation:
Cylinder formula = r^2 x pi x height
176 pi/11pi = 16
16 = r^2 x pi
16/ pi = r^2
r = sqrt(16/pi)
The triangles are similar by SAS principle.
<h3>How to know similar triangles?</h3>
Similar triangles have the same shape but may have different sizes.
In similar triangles, corresponding sides are always in the same ratio.
The corresponding angles are congruent.
Therefore, using SAS ratio,
6 / 8 = 8 × 3 / 32
6 / 8 = 24 / 32 = 3 / 4
Therefore, the corresponding sides are a ratio of each other.
Therefore, the triangles are similar by SAS principles because the two triangles have two pairs of sides in the same ratio and the included angles are also equal
learn more on similar triangle here: brainly.com/question/21480885
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Answer:
24.3
Step-by-step explanation:
because each side is the same. one has 12 inch and the other is 9. So you subtract 9 from 12 and get 3. Then you have to find out what the other mesurment is for the bigger shape, which is 2.7 because 32/12=2.66666, so u round and get 2.7 . so theen you multiply 9 and 2.7 and get 24.3! Hope this helps.
Answer:
We have the equation
![c_1\left[\begin{array}{c}0\\0\\0\\1\end{array}\right] +c_2\left[\begin{array}{c}0\\0\\3\\1\end{array}\right] +c_3\left[\begin{array}{c}0\\4\\3\\1\end{array}\right] +c_4\left[\begin{array}{c}8\\4\\3\\1\end{array}\right] =\left[\begin{array}{c}0\\0\\0\\0\end{array}\right]](https://tex.z-dn.net/?f=c_1%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D0%5C%5C0%5C%5C0%5C%5C1%5Cend%7Barray%7D%5Cright%5D%20%2Bc_2%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D0%5C%5C0%5C%5C3%5C%5C1%5Cend%7Barray%7D%5Cright%5D%20%2Bc_3%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D0%5C%5C4%5C%5C3%5C%5C1%5Cend%7Barray%7D%5Cright%5D%20%2Bc_4%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D8%5C%5C4%5C%5C3%5C%5C1%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D0%5C%5C0%5C%5C0%5C%5C0%5Cend%7Barray%7D%5Cright%5D)
Then, the augmented matrix of the system is
![\left[\begin{array}{cccc}0&0&0&8\\0&0&4&4\\0&3&3&3\\1&1&1&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D0%260%260%268%5C%5C0%260%264%264%5C%5C0%263%263%263%5C%5C1%261%261%261%5Cend%7Barray%7D%5Cright%5D)
We exchange rows 1 and 4 and rows 2 and 3 and obtain the matrix:
![\left[\begin{array}{cccc}1&1&1&1\\0&3&3&3\\0&0&4&4\\0&0&0&8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%261%261%261%5C%5C0%263%263%263%5C%5C0%260%264%264%5C%5C0%260%260%268%5Cend%7Barray%7D%5Cright%5D)
This matrix is in echelon form. Then, now we apply backward substitution:
1.
2.
3.
4.
Then the system has unique solution that is 
and this imply that the vectors 
are linear independent.
