Answer:
A
Step-by-step explanation:
First, 0 doesn't have any i values, so 0 is not pure imaginary.
Also, 0 <em>is</em> indeed a real number, so it is not a "non-real complex number."
Therefore, the only option left is that 0 is a complex number, and 0 is indeed a complex number.
The answer is A.
<span>The
third root of the given complex number 27(cos(pi/5)+isin(pi/5)) is <span>3(cos(pi/15)+i sin(pi/15))
</span>The solution would be like this
for this specific problem:</span>
<span>2^5 =
32 so you need a 2 out front the 5th root of cos(x) + i sin(x) is
cos(x/5) + i sin(x/5). Additionally, 5 roots are located at even
intervals around the circle. They are spaced every 2 pi/5 or 6 pi/15 radians.
</span>
<span>Roots
are located at pi/15, pi/15+ 10pi/15 = 11 pi/15 and pi/15+ 20pi/15 = 21 pi/15
(or 7 pi /5 ).</span>
You need to find the circumference of the whole circular pool and then subtract from it the arc length that is 1/4 of the circumference. The circumference formula is C = (3.14)(d), which in our case is 3.14(40) which is 125.6. Now we need the arc length we need to take away. 1/4 of a circle corresponds to a 90 degree angle, so in the formula for arc length, we have this:

which equals 31.4. Now subtract that from the circumference of the whole circle and you get the outside of the circle minus that arc length. That's 94.2. But we have to go in the radius times 2 to enclose the pie shaped piece we cut away. So we have 134.2. She should've just stuck with enclosing the circle; she would have used less fencing!
The answer is 6 since 2*6 is 12 and 12-8 is 4
Answer:
SSS, UVD, the answer is D
Step-by-step explanation:
90/9 = 10
70/7 = 10
80/8 = 10
triangle LMN congruent triangle UVD