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4 years ago

1+4=5 2+5=12 3+6=21 8+11=?

1 answer:

4 0

<span>1+4=5
2+5=12
3+6=21
8+11=?

The best way to answer this is to supply the missing or skipped equations to find the pattern.

</span><span>1+4=5
2+5=12
3+6=21
4+7=32
5+8=45
6+9=60
7+10=77
8+11=96

The final answer is 96 based on the pattern above.</span>

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A sandwich store charges a delivery fee to bring lunch to an office building. One office pays $33 for 4 turkey sandwiches. Anoth

shutvik [7]

Answer:

$12

Step-by-step explanation:

assuming that the cost of delivery is constant irrespective of the number ordered

Let the cost of sandwich be x

First office

$33=4x+c where c is the cost of delivery

Second office

$61=8x+c

These two are simultaneous equation. Subtracting the equation of first office from the second office we obtain

4x=28

Therefore, x=28/4=7

The cost of delivery is 33-(4*7)=33-28=5

Therefore, one sandwich plus delivery costs 7+5=$12

5 0

4 years ago

14. Set A contains all integers from 50 to 100, inclusive, and Set B contains all integers from 69 to 138, exclusive. How many i

tamaranim1 [39]

Answer:

Step-by-step explanation:

We have to make the intersection between these sets, and we see that they intersect in the range: [70,100], and d(70,100) = 30, that is the answer.

5 0

3 years ago

Find the measure of the marked acute angle to the nearest degree

Setler79 [48]

Answer: 62°
Solution:
tan x =34/18
x=tan^-1 (34/18)
x=62°

5 0

4 years ago

A picture representing 24÷6

Licemer1 [7]

Answer:

Step-by-step explanation:

24÷6

6 x ? = 24

6 goes into 24 four times

24÷6=4

7 0

3 years ago

Read 2 more answers

A manufacturer uses production method to produce steel rods. A random sample of 17 steel rods resulted in lengths with a standar

Arisa [49]

Answer:

$\chi^2 =\frac{17-1}{12.15} 22.09 =15.87$

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates $\alpha/2 =0.05$ of the area on each tail and we got:

$\chi^2_{crit}= 7.962$

$\chi^2_{crit}=26.296$

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is NOT significantly different from 3.5 cm

Confidence level method

We can find the p value like this

$p_v =2*P(\chi^2 >15.87)=0.92$

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is NOT significantly different from 3.5 cm

Step-by-step explanation:

Data provided

$n=17$ represent the sample selected

$\alpha=0.1$ represent the significance

$s^2 =4.7^2 =22.09$ represent the sample variance

$\sigma^2_0 =3.5^2 =12.15$ represent the value to check

Null and alternative hypothesis

We want to verify if the new production method has lengths with a standard deviation different from 3.5 cm, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 12.15$

Alternative hypothesis: $\sigma^2 \neq 12.15$

The statistic for this case is given by:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

The degrees of freedom are:

$df =n-1= 17-1=16$

$\chi^2 =\frac{17-1}{12.15} 22.09 =15.87$

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates $\alpha/2 =0.05$ of the area on each tail and we got:

$\chi^2_{crit}= 7.962$

$\chi^2_{crit}=26.296$

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is significantly different from 3.5 cm

Confidence level method

We can find the p value like this

$p_v =2*P(\chi^2 >15.87)=0.92$

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is significantly different from 3.5 cm

7 0

3 years ago