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nikitadnepr [17]
3 years ago
13

AHHH I just wanna know if what I put on the table is right ;-;​

Mathematics
2 answers:
yaroslaw [1]3 years ago
4 0

No, your answer is not correct. There was a total of 484 students surveyed, so your grand total at the bottom needs to be 484.

The first section that you will want to complete is the girls. They have given you each of the breakdowns, so you just need to add them together for the total number of girls.

36+55+144 = 235 girls.

Next, you know that you have 484 students, and if 235 are girls then 249 are boys. (484-235=). Enter 249 for the total boys.

Now you know that you have 249 boys, 40 always wear glasses and 161 never do. In order to calculate how many sometimes do you need to subtract 40 and 161 from 249.

249 - 40 - 161 = 48 sometimes wear glasses.

Now, you just need to add up each of the columns at the bottom. The answers are 76,

103 and 305. When you total these number together you get 484, which is the total number of students.

vfiekz [6]3 years ago
3 0

Yeah you did well on the table

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Answer:

56.7

Step-by-step explanation:

6.3^2 * 9^2= 56.7

5 0
2 years ago
when asked to write a point slope equation for a line passing through the points (-3,-5) and (2,4) a student wrote y-4=-9/5(x-2)
Eduardwww [97]
(-3,-5)(2,4)
slope(m) = (4 - (-5) / (2 - (-3) = (4 + 5) / (2 + 3) = 9/5

y - y1 = m(x - x1)
slope(m) = 9/5
(2,4)...x1 = 2 and y1 = 4
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y - 4 = 9/5(x - 1)....this is the correct answer

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5 0
3 years ago
Plz help me I will mark u Brainiest
Reika [66]

Answer: 1- quadrant 1 or top right

2- quadrant 4 or bottom right

3-quadrant 3 or bottom left

4 0
2 years ago
Read 2 more answers
. If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person
bulgar [2K]

Answer:

2.28% probability that a person selected at random will have an IQ of 110 or greater

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 100, \sigma = 5

What is the probability that a person selected at random will have an IQ of 110 or greater?

This is 1 subtracted by the pvalue of Z when X = 110. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{110 - 100}{5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% probability that a person selected at random will have an IQ of 110 or greater

5 0
3 years ago
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Keith_Richards [23]
This question has this set of answer choices:

a) when the plane cuts three faces of the cube, separating one corner from the others

b) when the plane passes through a pair of vertices that do not share a common face

c) when the plane is perpendicular to the base and intersects two adjacent vertical faces

d) when the plane makes an acute angle to the base and intersects three vertical faces

e) not enough information to answer the question

The right answer is the first choice: a) when the plane cuts three faces of the cube, separating one corner from the others

You can see a picture of this case in the figure attached: as you can see the cross section (in pink) is a triangle.

8 0
2 years ago
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