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3 years ago

AHHH I just wanna know if what I put on the table is right ;-;

Mathematics

2 answers:

yaroslaw [1]3 years ago

4 0

No, your answer is not correct. There was a total of 484 students surveyed, so your grand total at the bottom needs to be 484.

The first section that you will want to complete is the girls. They have given you each of the breakdowns, so you just need to add them together for the total number of girls.

36+55+144 = 235 girls.

Next, you know that you have 484 students, and if 235 are girls then 249 are boys. (484-235=). Enter 249 for the total boys.

Now you know that you have 249 boys, 40 always wear glasses and 161 never do. In order to calculate how many sometimes do you need to subtract 40 and 161 from 249.

249 - 40 - 161 = 48 sometimes wear glasses.

Now, you just need to add up each of the columns at the bottom. The answers are 76,

103 and 305. When you total these number together you get 484, which is the total number of students.

vfiekz [6]3 years ago

3 0

Yeah you did well on the table

You might be interested in

a. Suppose we had $15,192 cash and invested it in the bank at 16 percent interest, how much would you have at the end of 1, 2, 3

Goryan [66]

Answer:

Part a) $\$17,622.72$

Part b) $\$20,442.36$

Part c) $\$23,713.13$

Part d) $\$27,507.23$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part a) How much would you have at the end of 1 year?

in this problem we have

$t=1\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*1}=\$17,622.72$

Part b) How much would you have at the end of 2 year?

in this problem we have

$t=2\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*2}=\$20,442.36$

Part c) How much would you have at the end of 3 year?

in this problem we have

$t=3\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*3}=\$23,713.13$

Part d) How much would you have at the end of 4 year?

in this problem we have

$t=4\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*4}=\$27,507.23$

5 0

3 years ago

The perimeter of a rectangle is 192 ft. The ratio of its length to its width is 7 : 5. What are the dimensions of the rectangle?

ioda

P = 2(L + W)
P = 192

192 = 2(L + W)
192 / 2 = L + W
96 = L + W

length to width.....7:5...added = 12
7/12 * 96 = 672/12 = 56 ft <== ur length
5/12 * 96 = 480/12 = 40 ft <== ur width

7 0

3 years ago

If it is a regular polygon is then it is equilateral

OLEGan [10]

This might be a t or f. if this would be true,
regular polygons all contain an equal length in each side, polygons in general sometimes don't have equal sides. however, another kind of polygons are regular ones. those are polygons that use specific number of sides with the length of each one being the same
if it is false, polygons in general dont have equal sides.

4 0

3 years ago

Read 2 more answers

Hector must find the sum of 50 + 83 + 50 by using mental math. Which property allows Hector to simplify the equation to 50 + 50

olasank [31]

Answer:

183 A

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Identify a solution to this system of equations:

fomenos

Answer:

-4y+3y = -28+23

-y = -5

y = 5

thus x =-2

that is why b is right option

5 0

3 years ago

AHHH I just wanna know if what I put on the table is right ;-;​

AHHH I just wanna know if what I put on the table is right ;-;