If n is used as the initial amount of liquid in both A and B:
4(n-120) = n+120
4n-480 = n+120
3n = 600
n = 200
Each container originally held 200ml. Container A now has 80ml and Container B has 320ml
Hi there! :)
Solve for j(h(x)):
h(x) = x² + 4
j(x) = 4x - 1
Substitute in h(x) into "x":
j(h(x)) = 4(x² + 4) - 1
j(h(x)) = 4x² + 16 - 1
j(h(x)) = 4x² + 15
Solve at x = 2:
4(2)² + 15 = 4(4) + 15 = 31.
Answer:
240
Step-by-step explanation:
20 times 24 is 240
20 x 24 = 240
there is no triangle drawn
<span>So
let’s simplify the given situation.
We need to find out how much heavier is 91/8 lbs. compare to 2 5/6 lbs.
Since, it’s a combination of whole number and fraction; we cannot directly
subtract this given equation. We need to convert the two given number into a
fraction.
9 1/8 = 8 x 9 = 72 + 1 = 73, 73 is our numerator and 8 is our denominator
=> 73/8
2 5/6 = 6 x 2 = 12 + 5 = 17, 17 is our numerator and 6 is our denominator
=> 17/6
Now, we have 2 fractions with unlike denominator. In order to get a common
denominator, we have to find their least common factor.
=> <u>73</u> - <u>17 </u> = <u>73 x 6 </u> - <u>17 x 8 </u> <u>
</u> 8 6
8 x 6 6
x 8</span><span>
=> <u>438</u> – <u>136 </u> Now, we
have the same denominator, subtract</span><span>
48 48
=> <u>302 </u> or <u>151</u>
48 24
=> 6 <u>7</u>
24
Therefore 9 1/8 lbs. is 6 7/24 lbs. heavier than 2 5/6 lbs.</span>
