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Gwar [14]
3 years ago
6

Solve the inequality 2(4x + 1) < 3(2x - 3)

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
8 0
8x + 8 < 6x - 9
2x < -17
x < - 8,5
stiks02 [169]3 years ago
5 0

Answer:

x<-11/2

Step-by-step explanation

Try to isolate the variable by dividing it.

You might be interested in
25
user100 [1]

Answer:

this too difficult for my brain i don't like school

Step-by-step explanation:

7 0
2 years ago
A survey was done where males and females were asked if they would prefer to eat chicken or steak. The results of the survey are
alexgriva [62]

Answer:

Step-by-step explanation:

Number of tickets for international flights = 36

Total number of tickets = 95

The probability that a randomly selected airline ticket is for an international flight = 36 / 95 = 0.3789

The probability that a randomly selected airline ticket is for an international flight as a percent rounded to the nearest tenth of a percent = 0.3789 x 100 = 37.9%

% of males surveyed = 0.236 + 0.218 = 0.454 = 45.4%

% of males surveyed who prefer chicken = 0.236 out of 0.454 = 0.236 / 0.454 = 0.5198 = 51.58% = 52.0%

<em>hope this helps~</em>

6 0
3 years ago
Read 2 more answers
Solve for x please and quick please
alisha [4.7K]

Answer:

   x = √149 km

Step-by-step explanation:

Pythagorean theorem

x^2 = 10^2 + 7^2

x^2 = 100 + 49

x^2 = 149

   x = √149

4 0
3 years ago
Suppose that you are given a bag containing n unbiased coins. You are told that n-1 of these coins are normal, with heads on one
gladu [14]

Answer:

The (conditional) probability that the coin you chose is the fake coin is 2/(1 + n)

Step-by-step explanation:

Given

Total unbiased coin = n

Normal coins =n - 1

Fake = 1

The (conditional) probability that the coin you chose is the fake coin is represented by

P(Fake | Head)

And it's calculated as follows;

P(Fake | Head) = P(Fake, Head) ÷ P(Head) ----- (1)

Where P(Fake, Head) = P(Fake) * P(Head | Fake)

P(Fake) = 1/n --- because only one is fake

P(Head | Fake) = n/n because all coins (including the fake) have head

So, P(Fake, Head) = P(Fake) * P(Head | Fake) becomes

P(Fake, Head) = 1/n * n/n

P(Fake, Head) = 1/n

P(Head) is calculated by

P(Fake) * P(Head | Fake) + P(Normal) * P(Head | Normal)

P(Fake) * P(Head | Fake) = P(Fake, Head) = 1/n (as calculated above)

P(Normal) * P(Head | Normal) = ½ * (n - 1)/n ----- considering that the coin also has a tail with equal probability as that of the head.

Going back to (1)

P(Fake | Head) = P(Fake, Head) ÷ P(Head) becomes

P(Fake | Head) = (1/n) ÷ ((1/n) + (½(n-1)/n))

= (1/n) ÷ ((1/n) + (½(n-1)/n))

= (1/n) ÷ (1/n + (n - 1)/2n)

= (1/n) ÷ (2 + n - 1)/(2n)

= (1/n) ÷ (1 + n)/(2n)

= (1/n) * (2n)/(1 + n)

= 2/(1 + n)

Hence, the (conditional) probability that the coin you chose is the fake coin is 2/(1 + n)

5 0
3 years ago
14895 decreased by 3%
saveliy_v [14]
1448.15 is your answer
3 0
3 years ago
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