If the recipe needs 200g of chocolate bars, and that recipe feeds 8 people, you need to figure out how many times you'd have to make a recipe to feed 50 people.
50 is not a factor of 8, so we have to break the recipe down. if 200g of chocolate feeds 8 people, then it's safe to assume that 100g feeds 4 people, and 50g feeds 2 people.
The closest you get to 50 without exceeding it by a factor of 8 is 6 x 8= 48. You'd be missing the chocolate for two people, all you have to do is add 50 grams of a chocolate bar.
You have to multiply each ingredient by 6 therefore everything is exactly the same, just amplified. 200 x 6 =1200, which means you'd need 1200g of chocolate bars + 50g to make a mousse for 50 people.
Each chocolate bar has 150g, so now what you do is you get the 1250g and divide it by 150g. This will tell you the amount of chocolate bars you need to complete the recipe for 50 people. The answer is 8.33333, which means Tim will have to buy 9 chocolate bars.
Answer:
3r^2 /2
Step-by-step explanation:
r^3 cancels out r in the denominator remaining with r^2 in the numerator.
so 3r^2/2
= 3r^2 /2
Answer:
1/64, 1/256, 1/1024
Step-by-step explanation:
To get from 16 to 4 we multiply by 1/4
To get from 4 to 1 we multiply by 1/4
Each time we multiply by 1/4
The next term would be 1/16 * 1/4
1/16 * 1/4 = 1/64
The take that term 1/64 and multiply by 1/4
1/64*1/4 = 1/256
Finally take 1/256 and multiply by 1/4
1/256*1/4 =1/1024
Answer:
z = 2.1784 > 1.96,
Reject the null hypothesis
Step-by-step explanation:
For the males:
n1 = 162, x1 = 63
P1 = x 1/ n1 = 0.3889
For the Females:
n2 = 333,
x2 = 97
P 2 = x2/n2
= 0.2913
P 1= P2 Null hypothesis
P 1 is not equal to P 2 alternative hypothesis
Pooled proportion:
P= (x1 + x2) /( n1+ n2)
= (63 + 97) / (162 + 333)= 0.3232
Test statistics :
Z= (p1 - p2) /√p(1-p)× (1/n1 + 1/n2)
0.3889- 0.2913 / √0.3232 × 0.6768 × (1/162 +1/333)
=2.1784
c) Critical value :
Two tailed critical value, z critical = Norm.S .INV (0.05/2) = 1.960
Reject H o if z < -1.96 or if z > 1.96
d) Decision:
z = 2.1784 > 1.96,
Reject the null hypothesis
6%(5) = .30 6%
...........................................
