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3 years ago

What is the answer of 13/4*5/8?

Mathematics

2 answers:

sdas [7]3 years ago

7 0

In decimal form that is 2.03125, in fraction that would be 65/32

denpristay [2]3 years ago

6 0

65/48 is the answer
your welcome

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A(x-b)+bx-c=a+b, when a DOES NOT = -b ; FIND X PLEASE!!! WILL GIVE BRAINLIEST!!

tangare [24]

9514 1404 393

Answer:

x = (ab +a +b +c)/(a +b)

Step-by-step explanation:

Eliminate parentheses, subtract left terms not containing x, divide by the coefficient of x.

$a(x-b)+bx-c=a+b\\\\ax+bx-ab-c=a+b\\\\x(a+b)=ab+a+b+c\\\\\boxed{x=\dfrac{ab+a+b+c}{a+b}}$

6 0

2 years ago

A 9 cm tall cone shaped paper cup can hold up to 58.9 cm cubed of water. What is the minimum amount of paper needed to make the

babymother [125]

Volume of a cone, V = πr^2h/3

r = Sqrt 3V/πh = Sqrt [(58.9*3)/(3.14*9)] = 2.5 cm, minimum

Surface area, A = πr [r+ Sqrt (h^2+r^2)] = 3.14*2.5*[2.5+ Sqrt (9^2+2.5^2)] = 92.95 cm^2

Therefore, minimum amount of paper required is 92.95 cm^2

4 0

3 years ago

steve and scott are twins out for a morning jog. They run at the exact same speed They split at a corner one north, one east. On

trasher [3.6K]

Their running paths form the legs of an isosceles right triangle. The hypotenuse of such a triangle (the distance between Steve and Scott) is √2 times the length of one leg. Each has run 10 miles in the hour since they split.

They are running at 10 miles per hour.

4 0

3 years ago

There are big spenders among University of Alabama football season ticket holders. This data set Roll Tide!! shows the dollar am

Bas_tet [7]

Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:

$n = 479, \pi = \frac{130}{479} = 0.2714$

Hence the bounds of the interval are found as follows:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2714 - 1.96\sqrt{\frac{0.2714(0.7286)}{479}} = 0.2316$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2714 + 1.96\sqrt{\frac{0.2714(0.7286)}{479}} = 0.3112$

The 95% confidence interval is (0.2316, 0.3112).

More can be learned about the z-distribution at brainly.com/question/25890103

7 0

2 years ago

Can you please help me with the sheet??

OLga [1]

1. 25 minutes
2. 41 minutes
3. 21 wheels
4. 7
5. 160
6. 415 miles

7 0

2 years ago

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