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Alchen [17]
3 years ago
5

What are the coordinates for B

Mathematics
1 answer:
Molodets [167]3 years ago
7 0

Answer:

(-0.5, 0)

Step-by-step explanation:

'B' lies on the x-axis. This means that it's y-value is zero.

'B' also is in between '-1' and '0'. This means that the x-value is -0.5.

'B' should be (-0.5, 0).

Hope this helps.

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Answer:

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Step-by-step explanation:

cannot be a rhombus or square because all sides are not equal

cannot be a rectangle because the slopes indicate no right angles

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Solve the pair of linear equations....<br><br><br>Please help me by solving this!​
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In point form (2,1) equation form x = 2 y = 1
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3 years ago
Draw the graphs of the lines below on the same grid to find the coordinates of the point of intersection. y + 5 = 2 x y = 7 − 2
Butoxors [25]

Answer:

The point of intersection is (3,1)

Step-by-step explanation:

Manipulate these equations to achieve the form of y = mx + c

1) y + 5 = 2x

Y = 2x - 5

2) y = 7 - 2x

Y = -2x + 7

Point of intersection is (3,1) on the graph attached

To check algebraically:

2x - 5 = -2x + 7

4x = 12

X = 3

Substitute to get y

Y = 2x - 5

Y = 2 x 3 - 5

Y = 1

Therefore (3,1)

5 0
2 years ago
Solve x2 + 14x = −24 by completing the square.
Aleks04 [339]

Option A

The solution set of the equation is {-12, -2}

<h3><u>Solution:</u></h3>

Given equation is:

x^2 + 14x = -24

We have to find the solution set of this equation by completing the square

First, rearrange the equation so that only zero will be on the right side:

x^2 + 14x + 24 = 0 ----- eqn 1

<em><u>The general form of quadratic equation is:</u></em>

ax^2 + bx + c = 0 where a \neq 0

On comparing the given eqn 1 with general quadratic equation, we get

a = 1

b = 14

c = 24

In completing the square, we take half of coefficient of middle term "x" and then square it. Then we add it on both sides of the equation

So to complete the square, add (\frac{b}{2})^2 to both sides of the equation

x^2 + 14x + 24 + (\frac{14}{2})^2 = (\frac{14}{2})^2

x^2 + 14x + 24 + 7^2 = 7^2\\\\x^2 + 14x + 24 + 49 = 49

x^2 + 14x + 24 + 49 = 49\\\\x^2 + 14x + 49 = 49 - 24\\\\x^2 + 14x + 49 = 25\\\\(x + 7)(x + 7) = 25\\\\(x + 7)^2 = 25

Take square root on both sides

x + 7 = \sqrt{25}

x+7=\pm 5

Now make two equations

x + 7 = + 5 and x + 7 = -5

x = +5 - 7 = -2

x = -2

And,

x + 7 = -5

x = -5 - 7 = -12

x = -12

Therefore, the solution set of the equation is {-12, -2} and option A is correct

6 0
3 years ago
Read 2 more answers
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