1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aleksandr82 [10.1K]
4 years ago
14

Your school is selling granola bars for a fundraiser. They purchased 1250 granola bars and paid a delivery fee of $25. The total

cost including delivery fee, was $800. What was the cost of each granola bar? Define a variable, write an equation, and solve.
Mathematics
1 answer:
MariettaO [177]4 years ago
7 0
Hello!

First we have to define a variable.

Let x stand for the price of a granola bar

Then we have to make our equation

1250x + 25 = 800

This is the equation because the price for all the granola bars and delivery was $800

Now we solve it

Subtract 25 from both sides

1250x = 775

divide 1250 from both sides

x = 0.62

The cost for a granola bar is $0.62 or 62 cents

Hope this helps!
You might be interested in
A recreation center is offering special prices on its pool passes and gym memberships for the summer. On the first day of the of
s344n2d4d5 [400]

Answer:

In grade 8, students learned that some systems of linear equations have many solutions. This warm-up reminds students about this fact, while also prompting them to use what they learned in this unit to better understand what it means for a system to have infinitely many solutions.

The first equation shows two variables adding up to 3, so students choose a pair of values whose sum is 3. They notice that all pairs chosen are solutions to the system. Next, they try to find a strategy that can show that there are countless other pairs that also satisfy the constraints in the system. Monitor for these likely strategies:

Solving by graphing: The graphs of the two equations are the same line, so all the points on the line are solutions to the system.

Solving by substitution: The first equation can be rearranged to . Substituting for in the second equation gives or or . This equation is true no matter what is.

Solving by elimination: If we multiply the first equation by 4, rearrange the second equation to , and then subtract the second equation from the first, the result is . Subtracting from each side gives , which is true regardless of what or is.

Reasoning about equivalent equations: If we rearrange the second equation so that the variables are on the same side , we can see that this equation is a multiple of the first and are equivalent. This means they have the exact same solution set, which contains infinite possible pairs of and .

Identify students using different strategies and ask them to share their thinking with the class later.

Making graphing technology available gives students an opportunity to choose appropriate tools strategically (MP5).

Step-by-step explanation:

✒✒✏✂✂✏✒✏✒✂✏✂✏✒✂✒✂✂✂✏✂✒✂✂✂✒✏✏✏✒✒✏✏

7 0
3 years ago
How many cups of sugar is needed for 2 gallons?
Firdavs [7]
Depends on the need. for humming bird feeder about 3 - 4 cuos
7 0
3 years ago
Read 2 more answers
Can someone tell me what the answer is for x/-9≥3 as a simplified answer
Nostrana [21]
X/-9 ≥3 multiply both side by -9 to get rid of fraction
-9/1•x/-9 ≥-9•3
Cross cancel -9 on left side
x ≥ -27
6 0
3 years ago
Suppose y varies directly with x, and y=8 when x= -2. Find x when y=12
N76 [4]
X would be -3, -2*12 then divide 8
6 0
3 years ago
Read 2 more answers
HELP PLEASE !!! Place each expression under the equivalent expression in the table.
tino4ka555 [31]

Answer:

Option 3,5 are under first expression and Option 1,2 are under second expression.

Step-by-step explanation:

1). \frac{(x-4)(x+2)}{x^{2}+5x+6}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}

=\frac{(x-4)(x+2)}{(x+3)(x+2)}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}=\frac{(x-4)}{(x+3)}+\frac{-3x^{2}+24x-20}{(x+3)(4x-5)}

=\frac{(x-4)(4x-5)-3x^{2}+24x-20}{(x+3)(4x-5)}

=\frac{4x^{2}-5x-16x+20-3x^{2}+24x-20}{(x+3)(4x-5)}=\frac{x^{2}+3x}{(x+3)(4x-5)}

=\frac{x(x+3)}{(x+3)(4x-5)}=\frac{x}{4x-5}

2). \frac{3x}{4x-5}-\frac{4x^{2}}{8x^{2}-10x}=\frac{3x}{4x-5}-\frac{4x}{8x-10}=\frac{3x(8x-10)-4x(4x-5)}{(4x-5)(8x-10)}

=\frac{24x^{2}-30x-16x^{2}+20x}{(4x-5)(8x-10)}

=\frac{8x^{2}-10x}{(4x-5)(8x-10)}=\frac{x(8x-10)}{(4x-5)(8x-10)}=\frac{x}{4x-5}

3). \frac{6x^{2}}{x^{2}-7x+10}\div \frac{2x}{x-5}

=\frac{6x^{2}}{x^{2}-7x+10}\times \frac{x-5}{2x}

=\frac{3x(x-5)}{x^{2}-7x+10}

=\frac{3x(x-5)}{(x-5)(x-2)}=\frac{3x}{x-2}

4). \frac{-x}{4x-5}-\frac{4x^{2}}{16x^{2}-22x}

=\frac{-x}{4x-5}-\frac{2x}{8x-11}

=\frac{-x(8x-11)-2x(4x-5)}{(4x-5)(8x-11)}

=\frac{-8x^{2}+11x-8x^{2}+10x}{(4x-5)(8x-11)}

=\frac{-16x^{2}+21x}{(4x-5)(8x-11)}=\frac{-x(16x-21)}{(4x-5)(8x-11)}

5). \frac{3x^{2}}{x+3}\times \frac{2(x+3)}{2x^{2}-4x}

=\frac{6x^{2}(x+3)}{2x(x+3)(x-2)}=\frac{3x}{x-2}

6). \frac{5x^{2}}{x-2}\times \frac{2x+6}{8x^{2}-4x}

=\frac{10x^{2}(x+3)}{4x(x-2)(2x-1)}

4 0
3 years ago
Read 2 more answers
Other questions:
  • Please help.. Offering 25 points and 5 stars with a thanks
    6·2 answers
  • PLEASE, FAST, could someone help me out, I'm a bit confused :// ​
    7·1 answer
  • C=5/9 (f-32) solve for f
    10·1 answer
  • What is 500 multiplied by 5/6 as a mixed number
    12·2 answers
  • Please solve<br> 8-6(x-3) &gt;-4x+12
    15·2 answers
  • (4x + 1)°<br> 43°<br> PLEASE SOMEONE ONE HELPPPP!!
    9·2 answers
  • PLZ i need help, i will mark the brainlest
    7·2 answers
  • I need help I don’t lkdkdjxdkdjjddjdjdjd kdkdidjdjrke rikdjekrkdkdj dkdkdkdk
    9·1 answer
  • Find the equation of the line shown.​
    12·1 answer
  • Kevin and Randy Muise have a jar containing 65 ​coins, all of which are either quarters or nickels. The total value of the coins
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!