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larisa86 [58]
2 years ago
10

In which quadrant(s) do the graphs of y = x^2 and y = 3x +10 intersect?

Mathematics
1 answer:
vichka [17]2 years ago
5 0

Answer:

Step-by-step explanation:

y=3x+10

y=x²

x²-3x-10=0

x²-5x+2x-10=0

x(x-5)+2(x-5)=0

(x-5)(x-2)=0

x=5,2

when x=5,y=5²=25

point of intersection is (5,25)

when x=2

y=2²=4

so point of intersection is (2,4)

which shows that they intersect in first quadrant.

You might be interested in
What is two and three hundreds seventy thousandths in decimal form
givi [52]

Answer:

2.370

Step-by-step explanation:

In this, the word "and" means the decimal point so:

two and 3

=

2.3

so the tenths place would be the first number after the decimal point, you can think of it as counting backwards. 1000  100  10  "0"  0.1  0.01  0.001

                                                thousnd hundrd tn zro tnths hundrds thousndths

so the 3 hundred would be 0.3 and the sevenTY thousandths would be 0.070

so add that all up and you get:

2.370

or

two and three hundreds seventy thousandths

Hope this helped! Pls Brainliest! It would help and mean a lot! ; )

6 0
3 years ago
Please help y - (-10) = 12 <br> y = ______
kotykmax [81]
Subtracting a negative means that you will add the number. Convert the symbols to get the following:

y + 10 = 12

Subtract 10 from both sides.

y = 2


3 0
3 years ago
An isosceles right triangle has sides that are x+2 units long and a hypotenuse that is 8 units long. What is the length of the m
blsea [12.9K]

Answer:

In an isosceles right triangle, the hypotenuse is larger than the sides by a factor of the square root of 2.

So, if the hypotenuse is 8 then the sides are 8 / (sq root of 2) = 5.6568542495

Step-by-step explanation:

5 0
3 years ago
Solve n + 5(n - 1) = 7
Nina [5.8K]

Answer:

N = 2

Step-by-step explanation:

n + 5(n-1) = 7

n + 5n - 5 = 7

6n - 5 = 7

6n = 12

n = 2

HOPE THIS HELPS

PLZZ MARK BRAINLIEST!!!

7 0
3 years ago
Read 2 more answers
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Vinil7 [7]

Answer:

a)

X[bar]_A= 71.8cm

X[bar]_B= 72cm

b)

M.A.D._A= 8.16cm

M.A.D._B= 5.4cm

c) The data set for Soil A is more variable.

Step-by-step explanation:

Hello!

The data in the stem-and-leaf plots show the heights in cm of Teddy Bear sunflowers grown in two different types of soil (A and B)

To read the data shown in the plots, remember that the first digit of the number is shown in the stem and the second digit is placed in the leaves.

The two data sets, in this case, are arranged in a "back to back" stem plot, which allows you to compare both distributions. In this type of graph, there is one single stem in the middle, shared by both samples, and the leaves are placed to its left and right of it corresponds to the observations of each one of them.

Since the stem is shared by both samples, there can be observations made only in one of the samples. For example in the first row, the stem value is 5, for the "Soil A" sample there is no leaf, this means that there was no plant of 50 ≤ X < 60 but for "Soil B" there was one observation of 59 cm.

X represents the variable of interest, as said before, the height of the Teddy Bear sunflowers.

a) To calculate the average or mean of a data set you have to add all observations of the sample and divide it by the number of observations:

X[bar]= ∑X/n

For soil A

Observations:

61, 61, 62, 65, 70, 71, 75, 81, 82, 90

The total of observations is n_A= 10

∑X_A= 61 + 61 + 62 + 65 + 70 + 71 + 75 + 81 + 82 + 90= 718

X[bar]_A= ∑X_A/n_A= 218/10= 71.8cm

For Soil B

Observations:

59, 63, 69, 70, 72, 73, 76, 77, 78, 83

The total of observations is n_B= 10

∑X_B= 59 + 63 + 69 + 70 + 72 + 73 + 76 + 77 + 78 + 83= 720

X[bar]_B= ∑X_B/n_B= 720/10= 72cm

b) The mean absolute deviation is the average of the absolute deviations of the sample. It is a summary of the sample's dispersion, meaning the greater its value, the greater the sample dispersion.

To calculate the mean absolute dispersion you have to:

1) Find the mean of the sample (done in the previous item)

2) Calculate the absolute difference of each observation and the sample mean |X-X[bar]|

3) Add all absolute differences

4) Divide the summation by the number of observations (sample size,n)

For Soil A

1) X[bar]_A= 71.8cm

2) Absolute differences |X_A-X[bar]_{A}|

|61-71.8|= 10.8

|61-71.8|= 10.8

|62-71.8|= 9.8

|65-71.8|= 6.8

|70-71.8|= 1.8

|71-71.8|= 0.8

|75-71.8|= 3.2

|81-71.8|= 9.2

|82-71.8|= 10.2

|90-71.8|= 18.2

3) Summation of all absolute differences

∑|X_A-X[bar]_A|= 10.8 + 10.8 + 9.8 + 6.8 + 1.8 + 0.8 + 3.2 + 9.2 + 10.2 + 18.2= 81.6

4) M.A.D._A=∑|X_A-X[bar]_A|/n_A= 81.6/10= 8.16cm

For Soil B

1) X[bar]_B= 72cm

2) Absolute differences |X_B-X[bar]_B|

|59-72|= 13

|63-72|= 9

|69-72|= 3

|70-72|= 2

|72-72|= 0

|73-72|= 1

|76-72|= 4

|77-72|= 5

|78-72|= 6

|83-72|= 11

3) Summation of all absolute differences

∑ |X_B-X[bar]_B|= 13 + 9 + 3 + 2 + 0 + 1 + 4 + 5 + 6 + 11= 54

4) M.A.D._B=∑ |X_B-X[bar]_B|/n_B= 54/10= 5.4cm

c)

If you compare both calculated mean absolute deviations, you can see M.A.D._A > M.A.D._B. As said before, the M.A.D. summary of the sample's dispersion. The greater value obtained for "Soil A" indicates this sample has greater variability.

I hope this helps!

7 0
3 years ago
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