Question

In which quadrant(s) do the graphs of y = x^2 and y = 3x +10 intersect?

Answer 1

Answer:

Step-by-step explanation:

y=3x+10

y=x²

x²-3x-10=0

x²-5x+2x-10=0

x(x-5)+2(x-5)=0

(x-5)(x-2)=0

x=5,2

when x=5,y=5²=25

point of intersection is (5,25)

when x=2

y=2²=4

so point of intersection is (2,4)

which shows that they intersect in first quadrant.