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bekas [8.4K]
3 years ago
13

Solve pls brainliestsss

Mathematics
2 answers:
gayaneshka [121]3 years ago
5 0

formula

a = wl

solution

6 \times 40 = 240

Neko [114]3 years ago
4 0

Lol

6x40=240mm squared

240mm^{2}

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Mary rolls two dice. She adds the numbers on the two dice. What is the chance of this sum being twelve?
jonny [76]

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10%

Step-by-step explanation:

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G(x) appears to be a vertical expansion of f(x) by a factor of 3. f(x) appears to be
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so g(x) would be
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Find the greatest common factor.<br> бах2 + бах + ба
ad-work [718]

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6a

Step-by-step explanation:

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4 years ago
A circle has a radius of 9 inches. The Radius is multiplied by 2/3 to form a second circle. How is the ratio of the areas relate
liraira [26]

Answer:

\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81}{36} = (\frac{r_{1} }{r_{2}}) ^{2}

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Step-by-step explanation:

Radius of first circle (r_{1}) = 9 inches

Area of first circle = \pi r_{1} ^{2}

Area of first circle = 9 × 9 × π = 81 π

Now, since the radius is multiplied by 2/3 for from a new circle.

∴ Radius of the second circle = 9 \times \frac{2}{3} = 6\ inches

Area of second circle =  \pi r_{2} ^{2}

Area of second circle = 6 × 6 × π = 36 π

Now,

\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81\pi }{36\pi }

\frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)} = \frac{81}{36} = (\frac{9}{6}) ^{2} = (\frac{r_{1} }{r_{2}}) ^{2}

∵ (r_{1}) = 9 inches and (r_{2}) = 6 inches

The above expression shows that ratios of the areas of the circles are equal to the square of the ratio of their radii. i.e., \frac {radius\ of\ first\ circle)^{2} }{(radius\ of\ second\ circle)^{2} } = \frac {(Area\ of\ first\ circle) }{(Area\ of\ second\ circle)}

8 0
3 years ago
What is 3^2+4^2=c^2
nalin [4]

Answer:

c = +5 or c= -5, both are possible

Step-by-step explanation:

3^2 = 9

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c = + or - sqrt(25)

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4 0
3 years ago
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