Well it is triples you can tell that it is a division question. So triples means by 3.
The equation is 2,551,500 = d X 3^6. So, now 2,511,500 / 729 is your final answer, 3,500. Hope it helps :)
Answer:
Option C. Dicer
Explanation:
Dicer is a dsRNA endoribonuclease like bacterial Class III RNaseIII that is encoded by the DICER1 gene contains a N-terminal ATP-subordinate RNA helicase motif or domain.
Dicer cuts or cleaves precursor RNA molecules to make miRNA molecules. MicroRNAs regulates gene expression by hindering the procedure of protein creation. In the initial step of making a protein from a gene, another sort of RNA called RNA (mRNA) is made and goes about as the plan for protein production.
There are some possible answers which all mean the same thing:
- Produce fertile offspring
- Produce offspring
- Reproduce
→ Only individuals of a same species (sometimes genus) can reproduce because in order to reproduce animals need to have a similar genetic code, and there is now code more similar than the one of individuals of their own species.
Hope it helped,
BioTeacher101
Answer:
The correct answer is -
A) BbTt x bbTt
B) .5^4 or 1/16 or 0.0625
Explanation:
As it is given that Brachydactylus and PTC tasters both traits are autosomal dominant conditions which mean only one allele would be enough.
For Branchydactylus and For tasting : man and women will be heterogeneous.
Hence,
The Genotype of man = BbTt
The Genotype of wife = bbTt
b. Answer = 0.0625
For Branchydactylus:
Bb X bb
Possible genotypes:
B b
b Bb( Brachydactylus) bb(normal)
b Bb (Brachydactylus) bb (normal)
The probability of a single child being Branchydactylus = 2/4 = 0.5
So, Probability of all 4 child being Branchydactylus = .5 x .5 x .5 x .5 = 0.0625
Answer:
4 percent (4%)
Explanation:
A single crossover occurs between two (non-sister) chromatids belonging to homologous chromosomes. In this case, 16 percent of the meioses have a single crossover, thereby it will produce 8 percent of the chromosomes with the original (parental) combination in the progeny and the remaining 8 percent should be recombinants. From this result, it is reasonable to conclude that half of these recombinants should be 'Br' (and the other remaining 4 percent should be recombinants 'bR'), and therefore the answer is 4 percent (4%).
