Problem 1
<h3>Answers:</h3><h3>angle 6 = 50</h3><h3>angle 7 = 50</h3><h3>angle 8 = 40</h3>
--------------------
Work Shown:
point E = intersection point of diagonals.
x = measure of angle 6
y = measure of angle 8
angle 7 is also x because triangle AED is isosceles (AE = ED)
Focus on triangle AED, the three angles A, E, D add to 180
A+E+D = 180
x+80+x = 180
2x+80 = 180
2x = 180-80
2x = 100
x = 100/2
x = 50
So both angles 6 and 7 are 50 degrees.
Turn to angle 8. This is adjacent to angle 7. The two angles form a 90 degree angle at point A. This is because a rectangle has 4 right angles.
(angle7)+(angle8) = 90
50+y = 90
y = 90-50
y = 40
angle 8 = 40 degrees
=================================================
Problem 2
<h3>Answers:</h3><h3>angle 2 = 61</h3><h3>angle 3 = 61</h3>
--------------------
Work Shown:
Angle 5 is 29 degrees (given). So is angle 4 because these are the base angles of isosceles triangle DEC (segment DE = segment EC)
angle 3 and angle 4 form a 90 degree angle
x = measure of angle 3
(angle 3)+(angle 4) = 90
x+29 = 90
x = 90-29
x = 61
Angle 2 is congruent to angle 3 since triangle BEC is isosceles (BE = EC), so both angle 2 and angle 3 are 61 degrees each.
I think it is 32.00 dollars for 120 days
<span>I AM NOT SURE</span>
Answer:
It would be 0.73333333333.
Step-by-step explanation:
$2.00 in quarters is 8 quarters, since 1 quarter is 25 cents.
Out of those 8 quarters, only 3 are state quarters.
That means 5 are not state quarters.
So there is a 5/8 chance that the first quarter he takes out is not a state quarter.
If it is not, then there are 3 state quarters and 7 total quarters left, which means a 4/7 chance that the second quarter is not a state quarter.
To find the probability of both of these quarters not being state quarters, multiply the probabilities by each other.
4/7 • 5/8 = 20/56
Now simplify:
20/56 = 10/28 = 5/14
5/14 is in simplest form, so it is the answer.
So the answer is D. 5/14.
