All categories

3 years ago

A sphere has a volume of 7,234.56 units^3. Using 3.14 for pi, find the radius of the sphere. Record your answer on the grid.

Mathematics

1 answer:

Ann [662]3 years ago

4 0

Answer:

r = 1728 units

Step-by-step explanation:

Volume of sphere: V = (4/3)(pi)(r^3), were r is the radius.

Solving this for r^3, we get

V V 7234.56 units^3

------------- = r^3 = ---------------- so that --------------------------

(4/3)(pi) (4/3)(3.14) 4.19

Thus, r = 1728 units

You might be interested in

Can anyone help? grnheujghniuhwseruhuiwheriuh (Sorry about the letters just trying to get past the 20 words.)

babymother [125]

Answer:

8!!!

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A sociologist was investigating the ages of grandparents of high school students. From a random sample of 10 high school student

umka2103 [35]

Answer:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_{M}= 69.8$ represent the mean for the age of grandmother

$\bar X_{F}= 71.6$ represent the mean for the age of grandfather

$s_{M}= 8.38$ represent the sample deviation for the age of grandmother

$s_{F}= 6.65$ represent the sample deviation for the age of grandfather

$n_M = n_F= 10$

Solution to the problem

For this case the confidence interval is given by:

$(\bar X_{M} -\bar X_F) \pm t_{\alpha/2} \sqrt{\frac{s^2_M}{n_M} +\frac{s^2_F}{n_F}}$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_M +n_F-2=10+10-2=18$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that $t_{\alpha/2}=2.101$

And replacing we got:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

5 0

3 years ago

I NEED HELP FAST!!!!!!!!!! ⦁ Solve the equation. Describe the solution to the equation as one solution, no solution, or an infin

g100num [7]

$\frac{1}{8} (x + 24) = \frac{5}{8} x + 9 - \frac{1}{2} x \\ \\ \frac{x + 24}{8} = \frac{5}{8} x + 9 - \frac{1}{2} x \ / \ simplify \\ \\ \frac{x + 24}{8} = \frac{5x}{8} + 9 - \frac{1}{2} x \ / \ simplify \\ \\ \frac{x+ 24}{8} = \frac{5x}{8} + 9 - \frac{x}{2} \ / \ simplify \\ \\ \frac{x + 24}{8} = \frac{x}{8} + 9 \ / \ simplify \\ \\ x + 24 = x + 72 \ / \ multiply \ each \ side \ by \ 8 \\ \\ 24 = 72 \ / \ cancel \ x \\ \\ no \ solution \\ \\$

The final result is: no solution.

7 0

3 years ago

Read 2 more answers

Could you please help me to solve this query??

galina1969 [7]

Answer:

Show me problem

Step-by-step explanation:

I need a problem to solve it

3 0

3 years ago

I Really Don't Get Ratio, Can I Have Some Help?

lutik1710 [3]

Example:
If I give u a ratio of the number of teachers to students is 2:1 would mean that for every 2 teachers there is 1 student.

In question 10(a) the ratio of grey to black is 3:1 which means that the percentage would be 33%

In 10 (B) the ratio would be 6:4

3 0

3 years ago