Answer: none
Step-by-step explanation:
(A)
(16÷32/10) ×2 + 0.2×(90)
Using bodmas principle ; solve bracket
(16×10/32)×2 + (2/10×90)
10+18 =28
(B)
{(16÷32/10) × (2+2/10)} ×90
Open brackets
{(16×10/32) × (22/10)} ×90
(5×11/5) ×90
11×90 = 990
(C)
16÷{(32/10×2) + (2/10×8)} +82
Open brackets, solve division first, dolled by addition
16÷(32/5 + 8/5) +82
16÷(40/5) +82
16÷8 +82
2+82= 84
(D)
[16÷(32/10 ×2) + 0.2× (90)]
16÷ (32/5) + 2/10 ×90
Solve division
16×5/32 + 18
5/2 + 18
L.c.m of denominator (2&1) =2
(5+36) / 2 = 41/2
=20.5
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Hi there! The third option shows us the best setup.
We can find the area of a triangle with the standard formula area = 1/2 * base * height.
To be able to fill in this formula, we need to have a base and a height. We can't easily find a triangle with given base and height, so we must look for another option.
We can also take the area of a square (length × width) and then divide the answer by 2. This is possible when we take the third setup. Hence the third answer is correct.
Answer:
Step-by-step explanation:
Let x be gallons of 7%
Let y be gallons of 3%
364 = x + y
y = 364 - x
364(0.06) = x(0.07) + y(0.03)
364(6) = x(7) + y(3)
364(6) = 7x + 3y
364(6) = 7x + 3(364 - x)
364(6 - 3) = 7x - 3x
364(3) = 4x
x = 273
y = 364 - 273 = 91
273 gallons of 7%
91 gallons of 3%
