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aleksley [76]
3 years ago
9

Determine whether the point (1, 5) is a solution to the system of equations. Explain your reasoning in complete sentences.

Mathematics
2 answers:
nydimaria [60]3 years ago
6 0

Answer:

(1, 5) is not the solution.

Step-by-step explanation:

As we know the solution to a system of equations is defined by the point of intersection or common points of the given equations.

In this graph the point of intersection is given as (0,2) so the solution of the system of the equations will be the same point (0,2).

Therefore, (1,5) is not the solution to the system of equation.

Ivanshal [37]3 years ago
4 0
The solution to any system graphically can be found where the 2 graphs intersect.  These two graphs intersect at the point (0, 2). 
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On a blueprint, the scale indicates that 8 cm represent 16 feet. What is the length of a room that is 8.8 cm long and 3 cm wide
lana [24]
For the answer to the question above asking wWhat is the length of a room that is 8.8 cm long and 3 cm wide on the blueprint if <span>a blueprint, the scale indicates that 8 cm represent 16 feet?
</span>The room is 22.4 feet long

8cm=16ft
9.8cm=?ft

  8cm       9.8cm
______=______
  16ft          x ft

Cross multiply
8x=156.8
divide both sides by 8
x=19.6 ft
4 0
3 years ago
The revenue for a company producing widgets is given by y = -20x2 - 50x + 200, where x is the price in dollars for each widget.
lisov135 [29]

Answer:

The  price is   x =  $2.779

Step-by-step explanation:

From the question we are told that

  The  revenue is  y = - 20x^2  - 50 x + 200

   The cost of production is  y = 30 x - 10

Generally at break even point the cost of production is equal to the  revenue

So

      -20x^2 -50x + 200 =  30x-10

=>   20x^2 +20 -210 = 0

Using the quadratic formula to solve this equation we have that

       x =  $2.779

     

6 0
3 years ago
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What fractional part of one gallon would fit in one quart
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If a=2b^3 and b= -1/2c ^-2,express a in terms of c.
ElenaW [278]

Answer:

Part 1) a=-\frac{1}{4c^6}

Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})

simplify

a=-\frac{c^{6}}{4}

therefore

a=-\frac{1}{4c^{-6}}

6 0
3 years ago
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