Answer:
2 students study none of the subjects.
Step-by-step explanation:
Consider the attached venn diagram. First, we place that 1 student studies the three subjects. Then, we notice that 3 students study math and science, then 2 students study math and science only, since we have 1 that studies the three subjects. In the same fashion, we have that 3 students study Math and computer programming only (since they are 4 in total). Note that since 7 students study math, and we already have 6 students in our count in the math subject this implies that 1 student studies only math (the total number of students inside the math circle must add to 7).
We also have that 4 students study science and computer programming only. Which implies that we must have 3 students that study science only (10 students that study science in total) and 2 students study computer programming (for a total of 10 students). The total number of students that study none is the total number of students (18) minus the amount of students that is inside the circles (16) which is 2.
Answer:
Yes
Step-by-step explanation:
s<30
Put in 28 for s
28<30
Twenty eight is less than 30 so it is a solution
Answer:
Use the appropriate entry method for piecewise functions for the graphing calculator of interest.
Step-by-step explanation:
For Desmos, the entry looks like ...
f(x) = {x ≤ 2: -2x-1,-x+4}
_____
For a TI-84 calculator, the entry may look like ...
Y₁ = (-2X–1)(X≤2) + (-X+4)(X>2)
The symbols ≤ and > come from the TEST menu, which is the (2nd) shift of the MATH key.
Note that the function is the sum of the pieces, each piece multiplied by a test. For something like 0≤x<2, the multiplier would be a pair of tests:
... (0≤X)(X<2)
Answer:
no
Step-by-step explanation:
yes