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3 years ago

I need to find the Missing length again

Mathematics

2 answers:

GREYUIT [131]3 years ago

5 0

15-7 is 8! so 8 is the length of the side with the ?

dangina [55]3 years ago

4 0

8 is the eight would be the length of the missing angle

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What is the equation of a line that is parallel to the line y = 2x + 7 and passes through the point (–2, 4)? A. y = −12x + 3 B.

kvasek [131]

Answer:

the answer to this question is x=21

Step-by-step explanation:

Hope this didnt help

3 0

3 years ago

Read 2 more answers

12. Determine the slope of the line having the equation 2x + y = 12

Virty [35]

Answer:

b. -2

Step-by-step explanation:

Note the slope-intercept form: y = mx + b

Note that:

y = (x , y)

m = slope

x = (x , y)

b = y-intercept

First, isolate the variable, y. Note the equal sign, what you do to one side, you do to the other. Subtract 2x from both sides of the equation:

2x (-2x) + y = (-2x) + 12

y = -2x + 12

Remember, m is the variable for the term that stands for the slope (directly next to the x variable). In this case, your answer will be -2

b. -2 is your answer.

4 0

2 years ago

Read 2 more answers

If you are good at money and math, please look at the screenshot below and help me! I think some ppl will think this is easy.

Verizon [17]

Answer:

150 for lower seats and 200 for higher seats

Step-by-step explanation:

Need two equations and then solve using substitution method:

Equation 1 for tickets sold:

$35x + $25y = $10,250

Equation 2 for quantity (number #) of tickets sold:

x + y = 350

Use substitution method:

y = 350 - x

35x + 25 (350 - x) = $10,250

35x + $8750 - 25x = $10,250

10x + $8750 = $10,250

- $8,750 -$8,750

10x = 1,500

x = 150

y = 350 - 150

y = 200

Check the answers:

$35 (150) + $25 (200) =

$5,250 + $5,000 = $10,250

7 0

2 years ago

Please help me with these

pantera1 [17]

Answer:

domain: x ≥ -5

range: y ≥ 0

Step-by-step explanation:

notice the equation contains √x + 5

since anything inside a square root must not be negative, the domain is restricted to x + 5 ≥ 0 so solving for x, we have:

x ≥ -5 as the domain.

by inspecting the graph, the range is:

y ≥ 0

i hope this helps !!

3 0

3 years ago

Hw 28 shades figure

ra1l [238]

Answer:

Prat 9) $SF=2, x=16\ in$

Part 10) $SF=0.5, x=14\ ft$

Part 11) $SF=0.5, x=3.5\ ft$

Part 12) $SF=3, x=7\ m$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

SF-----> the scale factor

a----> area of the shaded figure

b----> area of the unshaded figure

$SF^{2} =\frac{x}{y}$

Problem 9) we have

$a=216\ in^{2}$

$b=54\ in^{2}$

substitute in the formula

$SF^{2}=\frac{216}{54}$

$SF^{2}=4$

$SF=2$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(2)(8)=16\ in$

Problem 10) we have

$a=161\ ft^{2}$

$b=644\ ft^{2}$

substitute in the formula

$SF^{2}=\frac{161}{644}$

$SF^{2}=0.25$

$SF=0.5$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(0.5)(28)=14\ ft$

Problem 11) we have

$a=10.5\ ft^{2}$

$b=42\ ft^{2}$

substitute in the formula

$SF^{2}=\frac{10.5}{42}$

$SF^{2}=0.25$

$SF=0.5$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(0.5)(7)=3.5\ ft$

Problem 12) we have

$a=4,590\ m^{2}$

$b=510\ m^{2}$

substitute in the formula

$SF^{2}=\frac{4,590}{510}$

$SF^{2}=9$

$SF=3$ ------> the scale factor

To find the value of x, divide the length of the shaded figure by the scale factor

$x=(21)/(3)=7\ m$

4 0

3 years ago