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kolezko [41]
2 years ago
12

Which of the following is designed to help an organization continue to operate during and after a disruption?

Computers and Technology
1 answer:
Olenka [21]2 years ago
7 0

Answer:

d

Explanation:

cause people need a care for there incedents that not expected thats why people need help prevent from a risk to save people lives

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Write a routine to interchange the mth and nth elements of a singly-linked list. You may assume that the ranks m and n are passe
IRINA_888 [86]

Answer:

//The routine to swap m th and nth ranked elements

void swapmAndn(int m, int n)

{

  //Set the linked list head node

  Linked_Node **node_head

  //To find the m ranked node

  //set previous node  

  Linked_Node *node_prev = NULL;

 

  //set node to store m ranked node as head node

  Linked_Node *node_current_m = *node_head;

 

  //set the rank as rm=1

  rm =1

  //traverse to find the m ranked node

  while (node_current_m && rm<m)

  {    

      node_prev = node_current_m;

      node_current_m = node_current_m->next;

      rm++;

  }

 

  //To find the n ranked node

  //set previous node  

  Linked_Node *node_prev_n = NULL;

 

  //set node to store n ranked node as head node

  Linked_Node *node_current_n = *node_head;

 

  //set the rank as rn=1

  rn =1

  //traverse to find the n ranked node

  while (node_current_n && rn<n)

  {    

      node_prev_n= node_current_n;

      node_current_n = node_current_n->next;

      rn++;

  }

 

  //if m is not first ranked node

  if (node_prev != NULL)

      //set node_current_n as previous node

      node_prev->next = node_current_n;

 

  //otherwise Set the node_current_n

  else

      *node_head = node_current_n;

 

  // If n is not first ranked node

  if (node_prev_n!= NULL)

      node_prev_n->next = node_current_m;

  else

      *node_head = node_current_m;

 

  //now swap the next pointers also

  //to make the swap process complete  

  Linked_Node *temp = node_current_n->next;

  node_current_n->next = node_current_m->next;

  node_current_m->next = temp;

}

Explanation:

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Cloud suites are stored on your hard drive and are available anywhere you can access the Internet
puteri [66]
Is that a question or an answer... im confused?!?!

5 0
3 years ago
One benefit of taking notes in class is that the student
MrMuchimi

Answer:

A

Explanation:

you got to listen if you want to be smart

4 0
3 years ago
in java how do i Write a program that reads a set of integers, and then prints the sum of the even and odd integers.
hammer [34]

Answer:

Here is the JAVA program:

import java.util.Scanner; //to take input from user

public class Main{

public static void main(String[] args) { //start of main function

Scanner input = new Scanner(System.in); // creates Scanner class object  

       int num, integer, odd = 0, even = 0; //declare variables

       System.out.print("Enter the number of integers: "); //prompts user to enter number of integers

       num = input.nextInt(); //reads value of num from user

       System.out.print("Enter the integers:\n"); //prompts user to enter the integers

       for (int i = 0; i < num; i++) { //iterates through each input integer

           integer = input.nextInt(); // reads each integer value

               if (integer % 2 == 0) //if integer value is completely divisible by 2

                   even += integer; //adds even integers

               else //if integer value is not completely divisible by 2

                   odd += integer;  } //adds odd integers

           System.out.print("Sum of Even Numbers: " + even); //prints the sum of even integers

           System.out.print("\nSum of Odd Numbers: " + odd);//prints the sum of odd integers

           }}

Explanation:

The program is explained in the comments mentioned with each line of the code. I will explain the logic of the program with the help of an example.

Suppose user wants to input 5 integers. So,

num = 5

Suppose the input integers are:

1, 2 , 3, 4, 5

for (int i = 0; i < num; i++)  is a for loop that has a variable i initialized to 0. The condition i<num is true because i=0 and num=5 so 0<5. Hence the statements inside body of loop execute.

At first iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 1

if (integer % 2 == 0) checks if integer is completely divisible by 2. The modulo operator is used which returns the remainder of the division and if this remainder is equal to 0 then it means that the integer is completely divisible by 2 and if the integer is completely divisible by 2 then this means the integer is even. 1%2 returns 1 so this means this condition evaluates to false and the integer is not even. So the else part executes:

odd += integer;   this becomes:

odd = odd + integer

odd = 1

Now the value of i is incremented to 1 so i=1

At second iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 2

if (integer % 2 == 0) checks if integer is completely divisible by 2. 2%2 returns 0 so this means this condition evaluates to true and the integer is even. So

even += integer;   this becomes:

even= even+ integer

even = 2

Now the value of i is incremented to 1 so i=2

At third iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 3

if (integer % 2 == 0) checks if integer is completely divisible by 2. 3%2 returns 1 so this means this condition evaluates to false and the integer is odd. So

odd += integer;   this becomes:

odd= odd + integer

odd= 1 + 3

odd = 4

Now the value of i is incremented to 1 so i=3

At fourth iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 4

if (integer % 2 == 0) checks if integer is completely divisible by 2. 4%2 returns 0 so this means this condition evaluates to true and the integer is even. So

even+= integer;   this becomes:

even = even + integer

even = 2 + 4

even = 6

Now the value of i is incremented to 1 so i=4

At fifth iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 5

if (integer % 2 == 0) checks if integer is completely divisible by 2. 5%2 returns 1 so this means this condition evaluates to false and the integer is odd. So

odd+= integer;   this becomes:

odd= odd+ integer

odd= 4 + 5

odd = 9

Now the value of i is incremented to 1 so i=5

When i=5 then i<num condition evaluate to false so the loop breaks. The next two print statement prints the values of even and odd. So

even = 6

odd = 9

Hence the output is:

Sum of Even Numbers: 6                                                                                                           Sum of Odd Numbers: 9  

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