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4 years ago

Fundamental types of data, such as strings, integers, and real numbers, are known as

Computers and Technology

1 answer:

alina1380 [7]4 years ago

4 0

Solution:

Fundamental types of data, such as strings, integers, and real numbers, are known as primative data type.

Primitive data structures are char, int, float, double. ... There comes derived data structures and user defined data structures. Derived data structures are also provided by the system but are made using premitives like an array, a derived data. It can be array of chars, array of ints.

Thus the right answer is primative data type.

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Crazy boy [7]

If any mistake was made using this type of primitive programming, the entire program of punch cards had to be re punched again. The correct option is A.

<h3>What is punch card?</h3>

A punch card is a card on which data is able to be recorded in the form of punched holes.

Whenever a mistake is done, the punched card is scrapped and made anew one for same programming.

Thus, if any mistake was made using this type of primitive programming. The entire program of punch cards had to be re punched again. The correct option is A.

Learn more about punch card.

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4 0

2 years ago

What is the IP address and TCP port number used by the client computer (source) that is transferring the file to gaia.cs.umass.e

lesya692 [45]

Answer:

Explanation:

5 0

3 years ago

Determine the number of bytes necessary to store an uncompressed RGB color image of size 640 × 480 pixels using 8, 10, 12 and 14

dexar [7]

Answer:

For 8 bits / Color Channel: 921, 600 bytes.

For 10 bits / Color Channel: 1,152,000 bytes.

For 12 bits / Color Channel: 1,382,400 bytes.

For 14 bits / Color Channel : 1,612, 800 bytes.

Explanation:

Un uncompressed RGB color image of 640 pixels wide by 480 pixels height (VGA resolution) uses 3 samples of x bits fin order to represent the quantity of each primary color (red, green and blue) in a given pixel of the image.

So, if we use 8 bits/ sample, we can calculate the bytes needed to store a complete image as follows:

640*480*3*8 bits = 7, 372,800 bits. (1)

As, by definition, 1 byte= 8 bits, we have:

Nº of bytes = 7,372,800 / 8 = 921,600 bytes. (2)

In order to get the bytes needed to store the same image, using 10, 12 and 14 bits/ sample, all we need is replacing 8 by 10, 12 and 14 in (1), and then dividing by 8 as in (2).

Proceeding in this way we obtain:

640*480*3*10 = 9,216,000 bits ⇒ 1,152,000 bytes.

640*480*3*12 = 11,059,200 bits ⇒ 1,382,400 bytes.

640*480*3*14= 12,902,400 bits ⇒ 1,612,800 bytes.

8 0

4 years ago

Print("Student" == "Teachers" or 99 != 88) will output False<br><br> true or false

ioda

Answer:

it will output True, so the statement is false

Explanation:

6 0

3 years ago

Suppose Host A wants to send a large file to Host B. The path from Host A to Host B has three links, of rates R1 = 500 kbps, R2

Vlad1618 [11]

Answer:

a) 500 Kbps b) 64 sec c) 320 sec

Explanation:

a) We define the throughput of a network, as the actual maximum transmission rate that the network is able to deliver, which in this case is equal to the lowest transmission rate of any of the links that the traffic must go through:

R1 =500 kbps

b) If the file size is given in bytes, and we have the throughput in bps, we need to convert to bits first, as follows:

4*10⁶ bytes * (8 bits/byte) = 32*10⁶ bits.

The time needed to transfer the file, will be given by the quotient between the file size and the throughput, as follows:

t = 32*10⁶ bits / 500*10³ bits/sec = 64 sec

c) If the transmission rate R2 is reduced to 100 kbps, R2 becomes the lowest transmission rate in the network, so it becomes the new throughput.

So, the time needed for the same file to be transferred to host B is as follows:

t= 32*10⁶ bits / 100*10³ bits/sec = 320 sec

6 0

3 years ago