Assuming your system of equations is
The answer is C. Infinitely many solutions. If my assumption is incorrect, then the answer will be likely different.
The reason why it's "infinitely many solutions" is because the first equation is the same as the second equation. The only difference is that everything was multiplied by -1. You could say that both sides were multiplied by -1.
Both equations given graph out the same line. They overlap perfectly yielding infinitely many solution points on the line.
60 minutes are in one hour.
Let's first think about how many possible outcomes there are to a series of coin flips. One that will help us here is that coin flips are <em>independent</em> - the outcome of one flip has no effect on the outcome of the others. What this means is that there are two possible outcomes <em />for <em>each </em>flip: heads or tails. For an example with fewer coins, let's say we were flipping 2 instead of five.
- Flip 1 can either be heads or tails
- Flip 2 can either be heads or tails
So our possible outcomes are HH, HT, TH, and TT. There are two possible second flips <em />for <em>each</em> of the possible first flips, or 2 x 2 = 4 total combinations of flips. Notice that <em>only one </em>of those combinations has zero tails - the combination with all heads.
If we were to flip a coin 5 times, we'd have two possible fifth flips for each of the two possible fourth flips for each of the two possible third flips for... it gets pretty hairy to describe in words, but I've attached a diagram so you can see how quickly it grows out of control. There are 2 x 2 x 2 x 2 x 2 or
possible combinations of heads and tails! But, in fact, we don't even need to sort through these 32 combinations to answer our question. <em>Every</em> combination will contain at least one tail, except one: the combination which contains all heads (HHHHH). Which means the rest of the 31 must contain at least one tail.
This fact will stay the same regardless of the number of coin flips you make: <em>the number of ways that contain at least one tail will always be the total number of combinations minus one (the case where all of the flips are heads).</em>
Answer:
pi*2^2*2sqrt3/3
if pi=3
8sqrt3
Step-by-step explanation:
Notice, the graph starts off with an account balance of $10, at the 10 over the y-axis, that means the initial amount in the account, or what he initially deposited was 10 bucks.
now... let's use any of the points, say hmm the 2, 10.44.
after 2 years, he's got an extra 44 cents in it, went up to 10.44.
bearing in mind that is a linear graph, and thus is a simple interest rate.
