What is the solution set for y < 3 /2 x – 4?
1 answer:
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Set up the given triangle on x-y coordinates with right angle at (0,0). So the two vertices are at (5,0) and (0,2![sqrt{x} n]{3}](https://tex.z-dn.net/?f=sqrt%7Bx%7D%20n%5D%7B3%7D%20)
)
let (a,0) and (0,b) be two vertices of the<span> equilateral triangle. So the third vertex must be at </span>
for a pt (x,y) on line sx+ty=1, the minimum of
equals to
smallest value happens at
so area is
hence m=75, n=67, p=3
m+n+p = 75+67+3 = 145
let (a,0) and (0,b) be two vertices of the<span> equilateral triangle. So the third vertex must be at </span>
for a pt (x,y) on line sx+ty=1, the minimum of
equals to
smallest value happens at
so area is
hence m=75, n=67, p=3
m+n+p = 75+67+3 = 145
62.5% of 56 is 35
Divide 35 and 56:
Convert the decimal to a percentage:
Divide 35 and 56:
Convert the decimal to a percentage: