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3 years ago

Plz make the graph (WILL MARK THE BEST ONE AS BRAINILIST)

Mathematics

2 answers:

shepuryov [24]3 years ago

8 0

X and y lollllll
i hope im marked as brainliest :))

Natalija [7]3 years ago

5 0

Answer:

x and y

Step-by-step explanation:

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What is the value of the expression 29-|7-11|

Makovka662 [10]

The value of 29 - |7 - 11| = 25

We have the following expression -

29 - |7 - 11|

We have to find its value.

<h3>Find the value of the expression -</h3><h3>X + | $\pi$ Y | where Y < 0</h3>

We have -

X + | $\pi$ Y |

Since Y < 0 - therefore $\pi$ Y < 0

Now -

|a| = - a { for a < 0}

Therefore -

X - $\pi$ Y

According to the question, we have -

29 - |7 - 11|

29 - | -4 |

29 - 4

Hence, the value of 29 - |7 - 11| = 25

To learn more about Modulus function, visit the link below-

brainly.com/question/13103168

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7 0

2 years ago

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A driver is 19 meters below the surface of the water. Use an integer to represent how far the driver will need to travel to reac

Tresset [83]

Answer:

19 metres

Step-by-step explanation:

3 0

2 years ago

The length of a rectangle is increasing at a rate of 4 meters per day and the width is increasing at a rate of 1 meter per day.

puteri [66]

Answer:

$\displaystyle \frac{dA}{dt} = 102 \ m^2/day$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Geometry

Area of a Rectangle: A = lw

l is length
w is width

Calculus

Derivatives

Derivative Notation

Implicit Differentiation

Differentiation with respect to time

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

$\displaystyle l = 10 \ meters$

$\displaystyle \frac{dl}{dt} = 4 \ m/day$

$\displaystyle w = 23 \ meters$

$\displaystyle \frac{dw}{dt} = 1 \ m/day$

Step 2: Differentiate

[Area of Rectangle] Product Rule: $\displaystyle \frac{dA}{dt} = l\frac{dw}{dt} + w\frac{dl}{dt}$

Step 3: Solve

[Rate] Substitute in variables [Derivative]: $\displaystyle \frac{dA}{dt} = (10 \ m)(1 \ m/day) + (23 \ m)(4 \ m/day)$
[Rate] Multiply: $\displaystyle \frac{dA}{dt} = 10 \ m^2/day + 92 \ m^2/day$
[Rate] Add: $\displaystyle \frac{dA}{dt} = 102 \ m^2/day$