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gladu [14]
4 years ago
14

During unfavorable conditions and amoeba forms a

Chemistry
2 answers:
Anika [276]4 years ago
6 0
A cyst forms when its in unfavorable conditions
zavuch27 [327]4 years ago
3 0
A cryst forms

Hope The Answer Helps! >.<
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What is the IUPAC name for the compound ZnO?
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The correct answer is option 1. THe IUPAC name for the compound ZnO is zinc oxide. It is an inorganic compound that is a white powder, insoluble in water and widely used as an additive in many materials and products. Most common application is as a skin cream.
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The ___ properties of elements repeat periodically when the ___ are arranged by ___ atomic number
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The properties of elements will repeat periodically when the elements are arranged by their atomic number.

Explanation:

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classify the materials based on their composition rock, clear liquids, peppercoms, concrete, salt, oxygen, birdseed, plant
USPshnik [31]

Answer:

1. rocks are composed of grains of minerals which are formed by the longest natural chemical reaction

2. clear liquids are mainly sugar and water . they are transparent food and mainly are beverages , ice , grains etc stuff

3. concrete is made up of basically three components . water , aggregate ( rock , sand and gravel ) and portland cement .

4. salt consist of NaCl it is made up of sodium and chloride it is also called rock or  halite salt

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3 years ago
The specific heat of asphalt is 920 J/kg °C. How much heat energy is required to raise the temperature of 113 kilograms of aspha
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8 0
4 years ago
A sample of helium gas has a volume of 1.50 L at 159 K and 5.00 atm. When the gas is compressed to 0.200 L at 50.0 atm, the temp
Brums [2.3K]

Answer:

ghdtgfgrdvreeeegrwwggegteefewqrwefrwerrftrtdsfgyuytfgererdf

Explanation:

The given data is as follows.

     V_{1} = 1.50 L,    T_{1} = 159 K,

      P_{1} = 5.00 atm,   V_{2} = 0.2 L,

       T_{2} = ?,       P_{2} = 50.0 atm  

And, according to ideal gas equation,  

               \frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Hence, putting the given values into the above formula to calculate the value of final temperature as follows.          

 \frac{5.0 atm \times 1.50 L}{159 K} = \frac{5 atm \times 0.2 L}{T_{2}}

            T_{2} = 21.27 K

Thus, we can conclude that the final temperature is 21.27 K .

5 0
3 years ago
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