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lara [203]
3 years ago
14

Write the balanced neutralization reaction that occurs between h2so4 and koh in aqueous solution. Phases are optional.

Chemistry
1 answer:
Nutka1998 [239]3 years ago
4 0

Answer:

The answer to your question is below

Explanation:

H₂SO₄ = sulphuric acid

KOH = potassium hydroxide

This is a neutralization reaction

                       H₂SO₄   +  2 KOH   ⇒     K₂SO₄   +  2H₂O

                                 2 -----------   K  ----------- 2

                                 1 -----------   S  ----------  1

                                 4 ----------   H  ---------   4

                                6 ------------   O ----------  6

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Answer:

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Explanation:

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p=0.855 g/cm^3

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Avogadro number = 6.02x10^23 atom/mol

a) the lattice parameter:

Since potassium has a cubic structure, its volume is equal to:

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a^3 =v

a=\sqrt[3]{v}=\sqrt[3]{1.5189x10^{-22} } = 5.3355x10^-8 cm

for a BCC structure, the atomic radius is equal to

r=\frac{ax\sqrt{3} }{4}=\frac{5.3355x10^{-8}x\sqrt{3}  }{4}=2.3103x10^{-8}cm

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