In an acid-base neutralization reaction, the equilibrium reaction would be between a weak base and its conjugate strong base. So, this must be the basis of the volume of added base.
<h3>What is pH ?</h3>
pH is used to measure whether the substance is acidic, basic or neutral and the range is 0 - 14.
<h3>What is Neutralization Reaction ? </h3>
Neutralization reaction is a chemical reaction in which an acid and a base react quantitatively with together.
Neutralization reaction equation:
Acid + Base → Salt + Water
Thus from the above conclusion we can say that In an acid-base neutralization reaction, the equilibrium reaction would be between a weak base and its conjugate strong base. So, this must be the basis of the volume of added base.
Learn more about the Neutralization reaction here: brainly.com/question/23008798
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"M" I believe is the symbol for molarity.
Answer:
False
Explanation:
Reactants are starting materials and are hence located at the left hand side of the equation while products are located at the right hand side.
Water-rich solutions carrying metallic salts fill cracks and form <u>veins</u>.
<u>Given:</u>
Mass of ice = mass of water = 5.50 kg = 5500 g
Temperature of ice = -20 C
Temperature of water = 75 C
<u>To determine:</u>
Mass of propane required
<u>Explanation:</u>
Heat required to change from ice to water under the specified conditions is:-
q = q(-20 C to 0 C) + q(fusion) + q (0 C to 75 C)
= m*c(ice)*ΔT(ice) + m*ΔHfusion + m*c(water)*ΔT(water)
= 5500[2.10(0-(-20)) + 334 + 4.18(75-0)] = 3792 kJ
The enthalpy change for the combustion of propane is -2220 kJ/mol
Therefore, the number of moles of propane corresponding to the required energy of 3792 kJ = 1 mole * 3792 kJ/2220 kJ = 1.708 moles of propane
Molar mass of propane = 44 g/mol
Mass of propane required = 1.708 moles * 44 g/mol = 75.15 g
Ans: 75.15 grams of propane must be combusted.
