Question

Which is an equation of the line containing the points (4, 10) and (6, 11) in standard form?

Answer 1

Answer:

Option C, x - 2y = -16

Step-by-step explanation:

Step 1:  Find the slope

$m = (y_2 - y_1) / (x_2 - x_1)$

$m = (11 - 10) / (6 - 4)$

$m = 1 / 2$

Step 2:  Plug in into point-slope form

$(y - y_1) = m(x - x_1)$

$(y - 10) = 1/2(x - 4)$

$y - 10 = 1/2x - 2$

Step 3:  Solve for x

$y - 10 + 2 = 1/2x - 2 + 2$

$(y - 8) * 2/1 = 1/2x * 2/1$

$2y - 16 = x$

Step 3:  Put the variables on one side

$2y - 16 - 2y = x - 2y$

$-16 = x - 2y$

$x - 2y = -16$

Answer: Option C, x - 2y = -16