Question

An object's position is given by x=bt+ct3, where b=1.50m/s and c=0.640m/s3. to study the limiting process leading to the instantaneous velocity, calculate the object's average velocity over time intervals from 1.00 s to 3.00 s.

Answer 1

X=bt + ct3, b=1.50m/s, c=0.640m/s3. 
Average velocity = distance / time
 ti = 1.00, tf = 3.00
 xi = (1.50)(1.00) + (0.640 )(1.00)^3 = 1.5 + 0.640 = 2.14 m
 xf = = (1.50)(3.00) + (0.640)(3.00)^3 = 4.5 + 27(17.28) = 21.78 m
 Ave Velocity = (21.78 - 2.14) / (3 - 1) = 9.82 m/s