Imaging techniques that use wave behaviors are -
- sonography
- X-ray radiography
- CT scan
<h3>How can mechanical waves help in the treatment of cancer?</h3>
Ultrasound is used to improve absorption of a radioactive pellet by a tumor. The radioisotope in a radiopharmaceutical releases sound waves into surrounding cells. Beams of X-rays are targeted at a cancerous tumor from outside the body.
<h3>How can mechanical waves help the treatment of cancer?</h3>
HIFU is a cancer treatment that uses high-frequency sound waves. You have HIFU from a machine. The machine gives off the sound waves which deliver a strong beam to a specific part of a cancer. This heats and destroys the cancer cells.
HIFU can treat a single tumour or part of a large tumour. But it is not suitable for people with cancer that has spread to more than one place in their body.
To learn more about cancer from the given link
brainly.com/question/11710623
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Answer: Speeding Up
Explanation:
Force is proportional to the acceleration of an object. The greater the force, the more acceleration will be produced.
When the force on the tire is equal to the weight of the car, the car is reaching a stability as a result of increase in motion.
But when the force of the load on the tire is quite large(most likely several times the weight of the car) and is directed forward, then, the car is at high speed.
Question
What is the length of the pipe?
Answer:
(a) 0.52m
(b) f2=640 Hz and f3=960 Hz
(c) 352.9 Hz
Explanation:
For an open pipe, the velocity is given by
Making L the subject then
Where f is the frequency, L is the length, n is harmonic number, v is velocity
Substituting 1 for n, 320 Hz for f and 331 m/s for v then
(b)
The next two harmonics is given by
f2=2fi
f3=3fi
f2=3*320=640 Hz
f3=3*320=960 Hz
Alternatively, 
and 
(c)
When v=367 m/s then
B. A stream of particles, or otherwise known as photons, small pieces of light. All of the rest of the options could never make a shadow.
Since acceleration is constant, we can use the formula
v² - u² = 2a ∆x
where v = final velocity, u = initial velocity, a = acceleration, and ∆x = displacement. Then
0² - (20.0 m/s)² = 2 (-4.20 m/s²) ∆x
⇒ ∆x = (20.0 m/s)² / (8.40 m/s²) ≈ 47.6 m
