Yes. Take for example a square and an ellipsis with the same perimeter. The family of ellipses with the same perimeter can have any area between that of a circle to zero (if it is extremely “thin” i.e. if its eccentricity is large). The circle has the maximum area of any other shape with the same perimeter, so the square has the same area of one of the intermediate ellipses.
Answer:
(a) 46°
(b) 86°
Step-by-step explanation:
When the secants cross externally (figure a), the angle where they cross is half the difference of the subtended arcs.
When they cross internally (figure b), the angle is half the sum of the subtended arcs.
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<h3>(a)</h3>
Half the difference of arcs VW and VX is ...
∠VYW = 1/2(160° -68°) = 46°
m∠VYW = 46°
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<h3>(b)</h3>
Half the sum of arcs AB and CD is ...
∠CED = 1/2(arc AB +arc CD)
2×∠CED = arc AB +arc CD . . . . . multiply by 2
2×∠CED -arc AB = arc CD . . . . . subtract arc AB
arc CD = 2×85° -84° = 86°
m arc CD = 86°
Answer:
Step-by-step explanation:
x - represents 1 point shots
(54 - x) - represents 2 point shots
x + 2(54 - x) = 89
x + 108 - 2x = 89
-x + 108 = 89
x = 19 (1 point shots)
54-x = 35 ( 2 point shots)
Test:
19 + 35 = 54 (total shots)
19 x 1 = 19
35 x 2 = 70
70 + 19 = 89 points
Answer:
She should have $4200 in the account after 24 weeks.
Step-by-step explanation:
Because this account has no interest and only increases its value because she adds $100 every week, we just multiply the number of weeks by 100 and add that to the $1800 she already has in the account.
