ur answer is C) Bubbles formed in the magma when it was still in liquid form.
Answer:
a)
85.05 N/m
b)
179.81 rad/s
Explanation:
a)
k = spring constant of the spring
m = mass of the block = 0.473 kg
x = stretch caused in the spring = 0.109 m
h = height dropped by the block = 0.109 m
Using conservation of energy
Spring potential energy gained by the spring = Potential energy lost by the block
(0.5) k x² = mgh
(0.5) k x² = mgx
(0.5) k x = mg
(0.5) k (0.109) = (0.473) (9.8)
k = 85.05 N/m
b)
angular frequency is given as
= 179.81 rad/s
Answer:
ρ₀ = 3λ/(2πR⁴)
Explanation:
If we take an elemental part of the cross sectional Area of the infinitely long cylinder.
The small elemental part has a small length dr in the cylinder's radial direction such that the cross sectional Area of the elemental part = 2πr dr
The linear density over the entire radial length of the cylinder will be equal to the sum of (volume charge density × elemental cross sectional Area)
That is,
λ = Σ ρ₀rR × 2πr dr
summing from 0 to R
λ = ∫ᴿ₀ (ρ₀rR × 2πr) dr
λ = ∫ᴿ₀ ρ₀R × 2πr² dr
λ = [ρ₀R × 2πr³/3 ]ᴿ₀
λ = (2π ρ₀R/3) [ r³ ]ᴿ₀
λ = (2π ρ₀R/3) [ R³ ]
λ = 2π ρ₀R⁴/3
ρ₀ = 3λ/(2πR⁴)
Answer:
Objective lens is the answer
Power in a wire where current is flowing can be calculated from the product of the square of the current and the resistance. Resistance is equal to the product of resistivity and length divided by the area of the wire. We do as follows:
Resistance = 2.44 × 10-8 ( 0.11) / (π)(0.0009)^2 = 1.055x10^-3 <span>Ω
P = I^2R = .170^2 (</span>1.055x10^-3 ) = 3.048x10^-5 W