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2 years ago

8

A skydiver jumps out of a hovering helicopter, so there is no forward velocity. Ignore wind resistance for this exercise. What i

s the skydiver's acceleration?

2 answers:

motikmotik2 years ago

8 0

Ignoring all air resistance, the sky diver's acceleration is 9.8 m/s^2 downward.

it wouldn't make any difference if he HAD any initial velocity at the moment he left the helicopter ... upward, downward, forward, backward, would not change his acceleration. It would still be 9.8 m/s^2, from the moment he left the chopper until the moment he hit the ground (or anything else)

ipn [44]2 years ago

3 0

Answer:

a = g

Explanation:

in this scenario, the diver is free-falling, hence his acceleration is equal to the pull of gravity

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3 years ago

An object is pushed from rest across a sheet of ice, accelerating at 8.0 m/s^2 [E] over a displacement of 1.05 m [E]. The object

tatiyna

Answer:

$D_T=18.567m$

Explanation:

From the question we are told that:

Acceleration $a=8.0 m/s^2$

Displacement $d=1.05 m$

Initial time $t_1=6.0s$

Final Time $t_2=2.5s$

Generally the equation for Velocity of 1.05 travel is mathematically given by

Using Newton's Law of Motion

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Generally the equation for Distance traveled before stop is mathematically given by

$d_2=v*t_1$

$d_2=3.098*4$

$d_2=12.392$

Generally the equation for Distance to stop is mathematically given by

Since For this Final section

Final velocity $v_3=0 m/s$

Initial velocity $u_3=4.1 m/s$

Therefore

Using Newton's Law of Motion

$-a_3=(4.1)/(2.5)$

$-a_3=1.64m/s^2$

Giving

$v_3^2=u^2-2ad_3$

Therefore

$d_3=\frac{u_3^2}{2ad_3}$

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