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yulyashka [42]
3 years ago
13

Choose the correct simplification of the expression (8x^4y^3)2

Mathematics
1 answer:
LuckyWell [14K]3 years ago
4 0

Answer:

16X*8Y*6

=............................

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during a hike, 3 friends equally shared 1/2 pound of trail mix. what amount of trail mix, in pounds, did each friends recieve
VashaNatasha [74]
1/2 divided by 3 is 1/6.
So your answer is 1/6 pounds each person.
7 0
3 years ago
Read 2 more answers
Cynthia Besch wants to buy a rug for a room that is 1919 ft wide and 2727 ft long. She wants to leave a uniform strip of floor a
yulyashka [42]

Answer:

The dimension of the rug would be 17 ft × 9 ft.

Step-by-step explanation:

Given

length of the room = 27 ft.

width of the room = 19 ft.

suppose, she leaves a uniform strip of x ft. around the rug.

So,

The length of rug = (27-2x)ft.

Width of rug= (19-2x)ft.

∴ Area of the rug= length×width

                            =  (27-2x)(19-2x)

                            =  513-54x-38x+4x^2

                            =   513-92x+4x^2

According to the question,

513-92x+4x^2=153

513-92x+4x^2-153=0        ( subtract 153 both sides)

4x^2-92x+360=0

4(x^2-23x+90)=0

x^2-23x+90=0

x^2-(18+5)x+90=0            ( Middle term splitting)

x^2-18x-5x+90=0

x(x-18)-5(x-18)=0

(x-5)(x-18)=0

x-5=0 or x-18=0             ( zero product property)

x=5 or x=18

if x=18, dimension would be negative  ( Not possible)

Thus, x= 5

Hence,

length of rug= 27-10=17 ft.

width of rug= 19-10=9 ft.

8 0
4 years ago
a marathon runner completes a 42km course at an average speed of 7km/h calculate the time taken to complete the course.
Ahat [919]

Answer:

6 hours

Step-by-step explanation:

42/7=6h

5 0
3 years ago
Find the maximum and minimum values of the function below on the horizontal span from 1 to 5. Be sure to include endpoint maxima
mote1985 [20]

Answer:

Max = 86; min = 36.54

Step-by-step explanation:

f(x) = x^{2} + \dfrac{85}{x}

Step 1. Find the critical points.

(a) Take the derivative of the function.

f'(x) = 2x - \dfrac{85}{x^{2}}

Set it to zero and solve.

\begin{array}{rcl}2x - \dfrac{85}{x^{2}} & = & 0\\\\2x^{3} - 85 & = & 0\\2x^{3} & = & 85\\\\x^{3} & = &\dfrac{85}{2}\\\\x & = & \sqrt [3]{\dfrac{85}{2}}\\\\& \approx & 3.490\\\end{array}\

(b) Calculate ƒ(x) at the critical point.  

f(3.490) = 3.490^{2} + \dfrac{85}{3.490} = 12.18 + 24.36 = 36.54

Step 2. Calculate ƒ(x) at the endpoints of the interval

f(1) = 1^{2} + \dfrac{85}{1} = 1 + 85 = 86\\\\f(5) = 5^{2} + \dfrac{85}{5} = 25 + 17 = 42

Step 3.Identify the maxima and minima.

ƒ(x) achieves its absolute maximum of 86 at x = 1 and its absolute minimum of 36.54 at x = 3.490

The figure below shows the graph of ƒ(x) from x = 1 to x = 5.

5 0
3 years ago
0.3 is 10% of what number?
Mariana [72]
0.03 i am thinking it is that because is 0.3 out of 10%
5 0
3 years ago
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