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3 years ago

Geometry question 3, Thanks if you help!

Mathematics

2 answers:

Simora [160]3 years ago

7 0

A~176.71 if I’m correct

Deffense [45]3 years ago

4 0

Answer:

A≈176.71

Step-by-step explanation:

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Write the quadratic equation of the parabola that passes through (-2,5) and has a vertex of (1,-3)

guapka [62]

-8/3x - 1/3 is the equation

6 0

3 years ago

Prove 2/sqrt3cosx+sinx=sec(pi/6-x)

dlinn [17]

Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved

We have to prove that

2/√3cosx + sinx = sec(Π/6-x)

To prove this we will solve the right-hand side of the equation which is

R.H.S = sec(Π/6-x)

= 1/cos(Π/6-x)

[As secƟ = 1/cosƟ)

= 1/[cos Π/6cosx + sin Π/6sinx]

[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]

= 1/[√3/2cosx + 1/2sinx]

= 1/(√3cosx + sinx]/2

= 2/√3cosx + sinx

R.H.S = L.H.S

Hence 2/√3cosx + sinx = sec(Π/6-x) is proved

Learn more about trigonometry here : brainly.com/question/7331447

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5 0

1 year ago

What is the length of BC , rounded to the nearest tenth?

Arte-miy333 [17]

Step $1$

In the right triangle ADB

Find the length of the segment AB

Applying the Pythagorean Theorem

$AB^{2} =AD^{2}+BD^{2}$

we have

$AD=5\ units\\BD=12\ units$

substitute the values

$AB^{2}=5^{2}+12^{2}$

$AB^{2}=169$

$AB=13\ units$

Step $2$

In the right triangle ADB

Find the cosine of the angle BAD

we know that

$cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}$

Step $3$

In the right triangle ABC

Find the length of the segment AC

we know that

$cos(BAC)=cos (BAD)=\frac{5}{13}$

$cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{13}{AC}$

solve for AC

$AC=(13*13)/5=33.8\ units$

Step $4$

Find the length of the segment DC

we know that

$DC=AC-AD$

we have

$AC=33.8\ units$

$AD=5\ units$

substitute the values

$DC=33.8\ units-5\ units$

$DC=28.8\ units$

Step $5$

Find the length of the segment BC

In the right triangle BDC

Applying the Pythagorean Theorem

$BC^{2} =BD^{2}+DC^{2}$

we have

$BD=12\ units\\DC=28.8\ units$

substitute the values

$BC^{2}=12^{2}+28.8^{2}$

$BC^{2}=973.44$

$BC=31.2\ units$

therefore

the answer is

$BC=31.2\ units$

8 0

3 years ago

Read 2 more answers

Factorize: Challenge problem: x^2+19x+78 help :)

Trava [24]

Answer:

(x + 6)(x + 13)

Step-by-step explanation:

Given

x² + 19x + 78

Consider the factors of the constant term (+ 78) whuch sum to give the coefficient of the x- term (+ 19)

The factors are + 6 and + 13 , since

6 ×13 = + 78 and 6 + 13 = + 19 , then

x² + 19x + 78 = (x + 6)(x + 13) ← in factored form

3 0

2 years ago

Read 2 more answers

a bag contains 10 white balls and 14 red balls.a ball is taken out of the bag,what is the probability that it is a red ball

Anit [1.1K]

Answer:

7/12

Step-by-step explanation:

Total = 10W+14R

probability of red = R/total

10+14 = 24 so total = 24

R = 14

14/24

reduce (divide by two on the top and bottom)

14/2

-------

24/2

= 7/12

3 0

3 years ago