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2 years ago

Please answer I give brainlist.

Mathematics

1 answer:

Ronch [10]2 years ago

6 0

Answer:

8. 14.7≅15 9. 2.88 10. 0.27 11. 125% 12. 62

Step-by-step explanation:

You might be interested in

The LCM of the three numbers is 48 what are the numbers ?

tatuchka [14]

Answer:

B. 6, 16, 24

Step-by-step explanation:

A: LCM(2, 3, 4) = 12

C: LCM(3, 8, 12) = 24

D: LCM(6, 8, 12) = 24

Only choice B lists 3 numbers whose LCM is 48.

3 0

3 years ago

There are $1.95 worth of nickels and quarters in a piggy bank there are three more nickels than quarters how many of each are in

Gennadij [26K]

Answer:

6 quarters and 9 nickels

Step-by-step explanation:

6 quarters is equal to $1.50. 6 nickels is equal to $0.30. Those together equal $1.80, then add the three nickels bringing your total to $1.95.

3 0

3 years ago

Read 2 more answers

100 random students are surveyed outside of the student center on campus. Let V denote that the student has a Visa credit card a

mote1985 [20]

Answer:

(a) The value of P (M | V) is 0.30.

(b) The value of $P (M^{c} | V)$ is 0.70.

(d) The value of $P(V^{c}|M)$ is 0.625.

Step-by-step explanation:

It is provided that,

V = a student has a Visa card

M = a student has a Master card

N = 100, n (V) = 40, n (M) = 32 and n (V ∩ M) = 12.

The probability of a student having visa card is:

$P(V) = \frac{n(V)}{N}= \frac{40}{100}=0.40$

The probability of a student having master card is:

$P(M) = \frac{n(M)}{N}= \frac{32}{100}=0.32$

The probability of a student having visa card and a master card is:

$P(V\cap M) = \frac{n(V\cap M)}{N}= \frac{12}{100}=0.12$

The conditional probability of an event, say A, given that another event, say B, has already occurred is,

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

(a)

Compute the probability that a student has a master card given that he/she has a visa card also, i.e. P (M | V) as follows:

$P(M|V)=\frac{P(V\cap M)}{P(V)} =\frac{0.12}{0.40}=0.30$

Thus, the value of P (M | V) is 0.30.

(b)

Compute the probability that a student does not have a master card given that he/she has a visa card also, i.e. $P (M^{c} | V)$ as follows:

$P (M^{c} | V)=1-P(M|V)=1-0.30=0.70$

Thus, the value of $P (M^{c} | V)$ is 0.70.

(c)

Compute the probability that a student has a visa card given that he/she has a master card also, i.e. P (V | M) as follows:

$P(V|M)=\frac{P(V\cap M)}{P(M)} =\frac{0.12}{0.32}=0.375$

Thus, the value of P (V | M) is 0.375.

(d)

Compute the probability that a student does not have a visa card given that he/she has a master card also, i.e. $P(V^{c}|M)$ as follows:

$P(V^{c}|M)=1-P(V|M)=1-0.375=0.625$

Thus, the value of $P(V^{c}|M)$ is 0.625.

8 0

3 years ago

WILL SEND EXTRA POINTS FOR RIGHT ANSWER HELP ASAP1

r-ruslan [8.4K]

$1191.02 this is the corect awnser

6 0

4 years ago

What is the solution to the system of equations?

cluponka [151]

Answer:

(-4,-8)

Step-by-step explanation:

3 0

3 years ago