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4 years ago

Solve the equation: -2/5 n = -30 A. n=-75 B. n=-12 C. n=12 D. n=75

2 answers:

6 0

Assuming your equation is: -2/5n = -30

-2/5n = -30 <- We get rid of the "/5n" by multiplying each side by 5n
-2 = -30 * 5n
-2 = -150n
-1 = -75n
75n = 1

But this doesn't match up with any of your answers, so if you wouldn't mind giving me the equation again, i'll work it out

Sonbull [250]4 years ago

5 0

two negatives make a positive, so the question is basically 2/5 x 30. 30/5 is 6, so 1/5 of 30 is 6. we want 2/5 so we double 1/5 and get 12. The correct answer is n.

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The China Company offers a trade-discount rate that is 4 times the complement of the trade-discount rate. If the list price is $

Natali5045456 [20]

Answer: See explanation

Step-by-step explanation:

Since the complement is the difference between 100% and discount rate. Since the China Company offers a trade-discount rate that is 4 times the complement of the trade-discount rate. Therefore, the discount rate will be 80% and the complement 20%.

Therefore, the trade discount will be:

= List price × Trade discount rate

= $58.75 × 80%

= $58.75 × 0.8

= $47

Net price = List price - Trade discount

= $58.75 - $47

= $11.75

7 0

3 years ago

(-17,70) (5,10) find the slope

Tju [1.3M]

Answer:

17.4

Step-by-step explanation:

To find your slope you take y2-y1/x2-x1

70-(-17)/10-5

87/5=

17.4

Hope this helps

6 0

3 years ago

PLS ANSWER (17points)

Kay [80]

Answer:

3. 14 cm

Step-by-step explanation:

Solve for radius first using the equation for circumference:

C = 2πr

44 = 2πr

44/2π = r

r = about 7 cm

d = 2r

d = 2*7

= 14 cm

4 0

3 years ago

Read 2 more answers

How to get the answers?

beks73 [17]

By inclusion/exclusion,

$n(P' \cup Q) = n(P') + n(Q) - n(P' \cap Q)$

We have

$n(\xi) = n(P) + n(P') \implies n(P') = 28 - n(P)$

so that

$n(P' \cup Q) = (28 - n(P)) + n(Q) - 2n(P) = 28 - 3n(P) + n(Q)$

Now,

$n(\xi) = 28 \implies n(P \cup Q) = 28 - 7 = 21$

and by inclusion/exclusion,

$n(P \cup Q) = n(P) + n(Q) - n(P \cap Q)$

Decompose $Q$ into the union of two disjoint sets:

$Q = (P \cap Q) \cup (P' \cap Q)$

Since they're disjoint,

$n(Q) = n(P\cap Q) + n(P'\cap Q) \implies n(Q) = n(P\cap Q) + 2n(P)$

$\implies n(P \cup Q) = n(P) + (n(P\cap Q) + 2n(P)) - n(P \cap Q)$

$\implies 21 = 3n(P)$

$\implies n(P) = 7$

From the Venn diagram, we see there are 3 elements unique to $P$ - by the way, this is the set $P \cap Q'$ - so $n(P\cap Q) = 7-3 = 4$ , and it follows that

$n(Q) = n(P\cap Q) + 2n(P) = 4 + 2\times7 = 18$

Finally, we get for (a)

$n(P' \cup Q) = 28 - 3n(P) + n(Q) = 28 - 3\times7 + 18 = \boxed{25}$

For (b), we have by inclusion/exclusion that

$n(P \cup Q') = n(P) + n(Q) - n(P \cap Q') = 7 + 18 - 3 = \boxed{22}$

5 0

2 years ago

A print shop orders 58 T-shirts. They order 16 pink T-shirts, and six times as many blue T-shirts as white T-shirts. How many bl

Pepsi [2]

The have ordered 36 blue T-shirts.
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How I got it --- So, we take away 16 from 58. You get 42.
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So, from then, you know 36 is 6 times as many as 6, right? ( Because 6 x 6 = 36)
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So, then, you have ordered 36 blue shirts and 6 white shirts, because 36 + 6 =42.
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Glad I could help, and good luck!
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3 0

3 years ago

Read 2 more answers