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2 years ago

Solve the equation: -2/5 n = -30 A. n=-75 B. n=-12 C. n=12 D. n=75

2 answers:

6 0

Assuming your equation is: -2/5n = -30

-2/5n = -30 <- We get rid of the "/5n" by multiplying each side by 5n
-2 = -30 * 5n
-2 = -150n
-1 = -75n
75n = 1

But this doesn't match up with any of your answers, so if you wouldn't mind giving me the equation again, i'll work it out

Sonbull [250]2 years ago

5 0

two negatives make a positive, so the question is basically 2/5 x 30. 30/5 is 6, so 1/5 of 30 is 6. we want 2/5 so we double 1/5 and get 12. The correct answer is n.

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If pr is 3x+14 and qr 7x-10 what is x

mr Goodwill [35]

Start the equation by putting the equations equal to each other 3x+14=7x-10
Next +10 on both sides
3x+14=7x-10
+10 +10
You are left with 3x+24=7x
because the 10's canceled each other out.
Next -3x on both sides
3x+24=7x
-3x +3x

You are left with 24= 10x
because like before the 3's canceled each other out
Now you will divide both sides by 10

24=10x
---- -----
10 10

2.4= X is the answer!

8 0

2 years ago

Which is the graph y = (x + 2) squared minus 3 ?

algol13

Answer:

I believe it's B

Step-by-step explanation:

On a coordinate plane, a parabola opens up and goes through (negative 3.75, 0), has a vertex at (negative 2, negative 3), and goes through (0, 1).

3 0

2 years ago

Determine if the following conditional statement is true or false,

Marat540 [252]

Answer:AlF3

Step-by-step explanation:

6 0

2 years ago

18 Given: the sequence 4, 7, 10, 13,...

Sergio039 [100]

a₁ = 4

n = 10

d = 3

a = a₁ + (n - 1)d

a₁₀ = 4 + (10 - 1)3

a₁₀ = 4 + (9)3

a₁₀ = 4 + 27

a₁₀ = 31

The 10th term would be 31 and the d variable will be replaced with the number 3.

8 0

1 year ago

Read 2 more answers

The ability to find a job after graduation is very important to GSU students as it is to the students at most colleges and unive

gtnhenbr [62]

Answer: (0.8468, 0.8764)

Step-by-step explanation:

Formula to find the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where $\hat{p}$ = sample proportion.

z* = Critical value

n= Sample size.

Let p be the true proportion of GSU Juniors who believe that they will, immediately, be employed after graduation.

Given : Sample size = 3597

Number of students believe that they will find a job immediately after graduation= 3099

Then, $\hat{p}=\dfrac{3099}{3597}\approx0.8616$

We know that , Critical value for 99% confidence interval = z*=2.576 (By z-table)

The 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation will be

$0.8616\pm(2.576)\sqrt{\dfrac{0.8616(1-0.8616)}{3597}}$

$0.8616\pm (2.576)\sqrt{0.0000331513594662}$

$\approx0.8616\pm0.0148\\\\=(0.8616-0.0148,\ 0.8616+0.0148)=(0.8468,\ 0.8764)$

Hence, the 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation. = (0.8468, 0.8764)

4 0

2 years ago