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wolverine [178]
3 years ago
7

A print shop orders 58 T-shirts. They order 16 pink T-shirts, and six times as many blue T-shirts as white T-shirts. How many bl

ue T-shirts did the print shop order ?
Mathematics
2 answers:
zlopas [31]3 years ago
8 0
36 blue, 6 white, and 16 red... = 58 t-shirts
Pepsi [2]3 years ago
3 0
The have ordered 36 blue T-shirts.
___________________

How I got it --- So, we take away 16 from 58. You get 42. 
________________________________________

So, from then, you know 36 is 6 times as many as 6, right? ( Because 6 x 6 = 36)
___________________________________________________________

So, then, you have ordered 36 blue shirts and 6 white shirts, because 36 + 6 =42.
______________________________________________________

Glad I could help, and good luck!
_________________________
_________________________
_________________________

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3y-6 divided by 9 = 4-2 divided by -3
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4 0
3 years ago
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compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.
Nina [5.8K]

\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})

We have been given two vectors $\vec{a}$ and $\vec{b}$, we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of$\vec{b}$onto $\vec{a}$means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

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$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

3 0
1 year ago
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valkas [14]
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3 0
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