Answer:
The rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.
Step-by-step explanation:
Given information:
A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station.


We need to find the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station.

According to Pythagoras


.... (1)
Put z=1 and y=2, to find the value of x.




Taking square root both sides.

Differentiate equation (1) with respect to t.

Divide both sides by 2.

Put
, y=2,
in the above equation.

Divide both sides by 2.



Therefore the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.
Answer:
Step-by-step explanation:
Difference in the distance = 50 yards
Difference in speed = 8 - 6 = 2 y/s
<u>Time to cover the gap is:</u>
<u>Sandra will run the distance:</u>
Product means to multiply.
306 x 15 = 4590.
B. Its suggesting something bigger than -5
845 miles / 13 hours = 65 miles per hour
65 miles per hour x 11 hours = 715 miles