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trapecia [35]
4 years ago
13

How to make a balanced chemical equation

Chemistry
1 answer:
Leona [35]4 years ago
7 0
Just get a triple balance beam and put chemicals on it to measure the weight
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Sufficient strong acid is added to a solution containing na2hpo4 to neutralize one-half of it. what will be the ph of this solut
Ivahew [28]
Assuming that the initial pH is pHi.
The initial concentration of [OH-] is
[OH]- = 10^(14 - pHi)

Since half of the Na2HPO4 is neutralized, the concentration of [OH-] will be reduced to half. The new pH will be
[OH-]/2 = 10^(14 - pHi)/2 = 10^(14 - pH)
14 - pHi - log 2 = 14 - pH
In terms of pHi,
pH = pHi + log 2
3 0
3 years ago
A solid form of matter in which there is long range repeating order is called ________
polet [3.4K]

Answer: A solid form of matter in which there is long-range repeating order is called crystalline.

Explanation:

A solid is crystalline if it has long-range order. Once the positions of an atom and its neighbors are known at one point, the place of each atom is known precisely throughout the crystal.

3 0
2 years ago
The following combinations are not allowed. If n and ml are correct, change the l value to create an allowable combination:
Lera25 [3.4K]

The allowable combination for the atomic orbital is n=4, l=2, m_{l}=2.

<h3>What are the three quantum numbers of an atomic orbital?</h3>

Three quantum numbers specify an atomic orbital:

- The principal quantum number, n, which is a positive integer, describes the relative size of the orbital and its distance from the nucleus.

- l is the angular momentum quantum number that is related to the shape of the orbital; l is an integer from 0 to n-1 (so n limits l ),

- $\boldsymbol{m}_{l}$ is the magnetic quantum number that prescribes the three-dimensional shape of the orbital around the nucleus; m_{l} values are integers from -l to =l(l limits ml)

For n = 4, l can four values: 0, 1, 2, and 3. To be consistent with m_{l}=+2the l value must be higher than 1. There are two l values that are consistent with n and m_{l} values:  l= 2 or 3

Therefore, the allowable condition is n=4, l=2, m_{l}=2

To know more about quantum numbers, visit: brainly.com/question/16979660

#SPJ4

3 0
2 years ago
A 20.0 ml sample of glycerol has a mass of 25.2 grams. What is the mass of 63 ml sample of glycerol?
poizon [28]

The mass of 63 ml sample : 79.38 g

<h3>Further explanation</h3>

Given

20 ml and 25.2 g of glycerol

Required

The mass of 63 ml sample

Solution

Density is the ratio of mass per unit volume

Density formula:

\large{\boxed {\bold {\rho~=~ \frac {m} {V}}}}

Density of glycerol :

= m : V

= 25.2 g : 20 ml

= 1.26 g/ml

Mass of 63 ml sample :

= density x volume

= 1.26 g/ml x 63 ml

= 79.38 g

7 0
3 years ago
2.50g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 12
Art [367]

Answer:

                      Molecular Formula  =  C₁₀H₈

Explanation:

Step 1: <u>Calculating Moles for each Element:</u>

C  =  Mass of CO₂ × (1 mol of CO₂÷ M.Mass of CO₂) × (1 mol of C ÷ 1 mol of CO₂)

C  =  8.60 g × (1 mol of CO₂÷ 44.011 g.mol⁻¹) × (1 mol of C ÷ 1 mol of CO₂)

C =  0.1954 mol

H  =  Mass of H₂O × (1 mol of H₂O ÷ M.Mass of H₂O) × (2 mol of H ÷ 1 mol of H₂O)

H  = 1.41 g × (1 mol of H₂O ÷ 18.106 g.mol⁻¹) × (2 mol of H ÷ 1 mol of H₂O)

H =  0.1557 mol

Step 2: <u>Calculate the Smallest whole number ratio as,</u>

                                 C                                                        H

                              0.1954                                               0.1557

                      0.1954/0.1557                                  0.1557/0.1557

                               1.25                                                       1

Multiply ratio by 4,

                                 5                                                         4

Result:

          Empirical Formula of Propane is C₅H₄

Step 3: <u>Calculate Molecular Formula:</u>

Molecular formula is calculated by using following formula,

                    Molecular Formula  =  n × Empirical Formula  ---- (1)

Also, n is given as,

                     n  =  Molecular Weight / Empirical Formula Weight

Molecular Weight  =  128.0 g.mol⁻¹

Empirical Formula Weight  =  5 (C) + 4 (H) =  64 g.mol⁻¹

So,

                     n  =  128.0 g.mol⁻¹ ÷ 64 g.mol⁻¹

                     n  =  2

Putting Empirical Formula and value of "n" in equation 1,

                    Molecular Formula  = 2 × C₅H₄

                    Molecular Formula  =  C₁₀H₈

4 0
3 years ago
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