Answer:
Exothermic. q = -542 kJ
Endothermic. q = 98.8 kJ
Explanation:
<em>When 1 mole of H₂(g) reacts with F₂(g) to form HF(g) according to the following equation, 542 kJ of energy are evolved. </em>
<em>H₂(g) + F₂(g) ⇄ 2 HF(g) </em>
<em>Is this reaction endothermic or exothermic? What is the value of q?</em>
Since the heat is evolved, the reaction is exothermic. When the reaction is exothermic, q is negative, that is, q = -542 kJ.
<em>When 1 mole of Fe₂O₃(s) reacts with H₂(g) to form Fe(s) and H₂0(g) according to the following equation, 98.8 kJ of energy are absorbed</em>
<em>Fe₂O₃(s) + 3 H₂(g) ⇄ 2 Fe(s) + 3 H₂O(g) </em>
<em>Is this reaction endothermic or exothermic? What is the value of q?</em>
Since the heat is absorbed, the reaction is endothermic. When the reaction is endothermic, q is positive, that is, q = 98.8 kJ.
Water and sodium oxide have different properties because of their nature as explained below.
<h3><u>Explanation:</u></h3>
Sodium oxide is a oxide of metallic sodium, while water is an oxide of hydrogen. So sodium oxide is a metallic oxide, while water is a non metallic oxide. Sodium oxide is a basic oxide, while water is neutral. As state of matter is concerned, sodium oxide is solid in normal room temperature, while water is liquid in normal room temperature. Water is a polar covalent molecule with partial charges on oxygen, but sodium oxide is an ionic molecule.
So all these factors contribute to very different properties of both sodium oxide and water.
Answer:
110 degree
Explanation:
This is because Hybridization of an s orbital with all three p orbitals (px , py, and pz) results in four sp3 hybrid orbitals. sp3 hybrid orbitals are oriented at bond angle of 109.5 degrees from each other. This 109.5 degrees gives an arrangement of tetrahedral geometry
The answer is potassium magnate
