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Pani-rosa [81]
2 years ago
13

When methane, CH4, is combusted, it produces carbon dioxide, CO₂, according to the unbalanced equation: CH4 +0₂ - CO₂ + H₂O.

Chemistry
1 answer:
nevsk [136]2 years ago
3 0

The balanced equation will be CH_4 + 2O_2 --- > CO_2 + 2H_2O

<h3>Stoichiometric problems</h3>

The balanced equation of the reaction would be as follows:

CH_4 + 2O_2 --- > CO_2 + 2H_2O

The mole ratio of methane to carbon dioxide is 1:1.

10 grams of methane will give 10/16 = 0.625 moles

0.625 moles of carbon dioxide would give 0.625 x 44.01 = 27.506 grams.

Thus, 10 grams of methane will produce approximately 27 grams of carbon dioxide stoichiometrically.

The reaction obeys the law of conservation of mass because the atoms of all the elements before and after the reaction are balanced.

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

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3 years ago
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3 years ago
Which has the higher percentage of aluminum, Al2O, or Al(NO3)3
Rzqust [24]

Al₂O  has a higher percentage of aluminium.

Explanation:

To solve this problem, we have to compare the molar mass of the aluminium in each compound to one another as percentage of the whole compound:

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8 0
3 years ago
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7 0
3 years ago
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What is the mass percent of oxygen (0) in SO2?
vazorg [7]

Answer:

D. (16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%

Explanation:

Step 1: Detemine the mass of O in SO₂

There are 2 atoms of O in 1 molecule of SO₂. Then,

m(O) = 2 × 16.0 g = 16.0 g + 16.0 g = 32.0 g

Step 2: Determine the mass of SO₂

m(SO₂) = 1 × mS + 2 × mO = 1 × 32.1 g + 2 × 16.0 g = 32.1 g + 16.0 g + 16.0 g = 64.1 g

Step 3: Detemine the mass percent of oxygen in SO₂

We will use the following expression.

m(O)/m(SO₂) × 100%

(16.0 g + 16.0 g) × 100% / (32.1 g + 16.0 g + 16.0 g) = 49.9%

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3 years ago
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