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Pani-rosa [81]
2 years ago
13

When methane, CH4, is combusted, it produces carbon dioxide, CO₂, according to the unbalanced equation: CH4 +0₂ - CO₂ + H₂O.

Chemistry
1 answer:
nevsk [136]2 years ago
3 0

The balanced equation will be CH_4 + 2O_2 --- > CO_2 + 2H_2O

<h3>Stoichiometric problems</h3>

The balanced equation of the reaction would be as follows:

CH_4 + 2O_2 --- > CO_2 + 2H_2O

The mole ratio of methane to carbon dioxide is 1:1.

10 grams of methane will give 10/16 = 0.625 moles

0.625 moles of carbon dioxide would give 0.625 x 44.01 = 27.506 grams.

Thus, 10 grams of methane will produce approximately 27 grams of carbon dioxide stoichiometrically.

The reaction obeys the law of conservation of mass because the atoms of all the elements before and after the reaction are balanced.

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

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Answer:

The mass of 10 cm³of a 0.4 g/dm³ solution of sodium carbonate is 0.004 grams

Explanation:

The question is with regards to density calculations

The density of the given sodium carbonate solution, ρ = 0.4 g/dm³

The volume of the given solution of sodium carbonate, V = 10 cm³ = 0.01 dm³

Density \ of \ an \ object, \rho  = \dfrac{The \ mass \ of \ the \ object, \ m }{\ The \ volume \ of \ the \ object, \ V }

\rho = \dfrac{m}{V}

Therefore, we have;

The \ Density \ of \ the \ sodium \ carbonate, \ \rho  = 0.4 \ g/dm^3 =  \dfrac{m }{ 0.01 \ dm^3 }

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The mass of 10 cm³ (10 cm³ = 0.01 dm³) of a 0.4 g/dm³ solution of sodium carbonate, m = 0.004 g.

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An element has ccp packing with a face-centered cubic unit cell. its density is 8920 kg/m3 and the unit cell volume is 4.72 x 10
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<span>63.4 g/mol
   First, let's determine how many atoms per unit cell in face-centered cubic. There is 8 corners, each of which has 1 atom, and each of those atoms is shared between 8 other unit cells. So 8*1/8 = 1 atom per unit cell. Additionally, there are 6 faces, each of which has 1 atom that's shared between 2 unit cells. So 6*1/2 = 3 atoms per unit cell. So each unit cell has the mass of 1+3 = 4 atoms. Since there is 1000 liters per cubic meter, the mass per liter is 8920 kg/1000 = 8.920 kg/L. Now the mass per unit cell is 8920 g * 4.72x10^-26 = 4.21024x10^-22 g per unit cell. The mass per atom is 4.21024x10^-22 g / 4 = 1.05256x10^-22 g/atom, Finally, multiply by Avogadro's number, getting 1.05256x10^-22 g/atom * 6.0221409x10^23 atom/mol = 63.38664625704 g/mol.
   Rounding to 3 significant digits gives 63.4 g/mol.</span>
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