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valentina_108 [34]
4 years ago
13

How many daughter cells are created from mitosis and cytokinesis?

Chemistry
1 answer:
mixas84 [53]4 years ago
4 0
<span>Mitosis creates 2 daughter cells which are diploid. These products are genetically identical. Meiosis produces 4 daughters cells which are haploid. These products are genetically different.</span>
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What is the concentration of the murexide soution with a transmittance of 28.65%. (molar absorptivity = 3847)
Ainat [17]

Answer:

The concentration of the murexide solution is 0.0000745 M

Explanation:

From Beer-Lambert's law,

A = εlc

A = Absorbance = 28.65% = 0.2865

ε = molar absorptivity = 3847 M/cm

l = path length = 1cm

c = concentration in mol/L = ?

c = A/εl = 0.2865/(3847×1) = 0.0000745 mol/L

Hope this Helps!

6 0
3 years ago
Calculate the total energy, in kilojoules, that is needed to turn a 46 g block
neonofarm [45]

Answer: The total energy, in kilojoules, that is needed to turn a 46 g block of ice at -25 degrees C into water vapor at 100 degrees C is 11.787 kJ.

Explanation:

Given: Mass = 46 g

Initial temperature = -25^{o}C

Final temperature = 100^{o}C

Specific heat capacity of ice = 2.05 J/g^{o}C

Formula used to calculate the energy is as follows.

q = m \times C \times (T_{2} - T_{1})

where,

q = heat energy

m = mass

C = specific heat capacity

T_{1} = initial temperature

T_{2} = final temperature

Substitute the values into above formula as follows.

q = m \times C \times (T_{2} - T_{1})\\= 46 g \times 2.05 J/g^{o}C \times (100 - (-25))^{o}C\\= 11787.5 J (1 J = 0.001 kJ)\\= 11.787 kJ

Thus, we can conclude that the total energy, in kilojoules, that is needed to turn a 46 g block of ice at -25 degrees C into water vapor at 100 degrees C is 11.787 kJ.

7 0
3 years ago
An element that is likely to have this property is; A. bromine B. carbon C. sodium D. tellurium ?
vladimir2022 [97]
The answer is D. Most common semiconducting materials are crystalline solids. A<span>morphous and liquid semiconductors are also known to be.</span>
4 0
4 years ago
Read 2 more answers
Consider the titration of 30.0 mL of 0.050 M NH3 with 0.025 M HCl.
Alla [95]

Answer:

60.0mL

Explanation:

For the process of titration , the formula we use is -

M₁V₁ = M₂V₂

Where ,

M₁ = initial concentration

V₁ = initial volume

M₂ = final concentration

V₂ = final volume .

Hence , from the question ,

The given data is ,

M₁ = 0.050 M

V₁ = 30.0mL

M₂ = 0.025 M

V₂ = ?

Now, to determine the unknown quantity , the formula can be applied ,

Hence ,

M₁V₁ = M₂V₂

Putting the respective values ,

0.050 M * 30.0mL = 0.025 M * ?

solving the above equation ,

V₂ = ? = 60.0mL

6 0
4 years ago
How can litmus paper and phenolphthalein be used to tell whether a solution is an acid or a base? Be specific.
MArishka [77]
Both litmus paper and phenolphthalein are used as acid/base (pH) indicators.

Litmus paper:
Litmus paper will turn either blue or red when a drop of solution is added to the paper. Red indicates an acidic solution (pH is <4.5), and blue indicates a basic solution (pH >8.3).

Phenolphthalein:
Phenolphthalein is commonly used during acid/base titrations. When the solution is acidic and the indicator is added, it will remain colorless. If the solution is basic, the phenolphthalein will turn pink.
6 0
4 years ago
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