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notsponge [240]
3 years ago
11

Choose the most appropriate name for the function described below. The postage required to mail a box depends on its weight

Mathematics
2 answers:
Stells [14]3 years ago
6 0

Answer:

Postage(weight) or p(w)

Step-by-step explanation:


anzhelika [568]3 years ago
3 0

Answer:

Postage(weight), or p(w)

I hope this is correct if it is then I hope it helps.

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Please could you find the answers to the questions in the attachment.
Fudgin [204]
(\frac{x1+x2}{2} , \frac{y1+y2}{2})we need 3 equations
1. midpoint equation which is  (\frac{x1+x2}{2} , \frac{y1+y2}{2}) when you have 2 points

2. distance formula which is D= \sqrt{(x2-x1)^{2}+(y2-y1)^{2}}

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height


so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=(\frac{11+19}{2} , \frac{10+6}{2})
midpoint=(\frac{30}{2} , \frac{16}{2})
midpoint= (15,8)

point x=(15,8)



y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=(\frac{5+21}{2} , \frac{8+0}{2})
midpoint=(\frac{26}{2} , \frac{8}{2})
midpoint=(13,4)

Y=(13,4)



legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= \sqrt{(19-11)^{2}+(6-10)^{2}}
D= \sqrt{(8)^{2}+(-4)^{2}}
D= \sqrt{64+16}
D= \sqrt{80}
D= 4 \sqrt{5}
BC=4 \sqrt{5}





X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= \sqrt{(13-15)^{2}+(4-8)^{2}}
D= \sqrt{(-2)^{2}+(-4)^{2}}
D= \sqrt{4+16}
D= \sqrt{20}
D= 2 \sqrt{5}
XY=2 \sqrt{5}


the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC=4 \sqrt{5} and XY=2 \sqrt{5}

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= \sqrt{(21-5)^{2}+(0-8)^{2}}
D= \sqrt{(16)^{2}+(-8)^{2}}
D= \sqrt{256+64}
D= \sqrt{320}
D= 4 \sqrt{2}
AD=4 \sqrt{2}


so we have
AD=4 \sqrt{2}
BC=4 \sqrt{5} 
XY=2 \sqrt{5}

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
(4 \sqrt{2}+4 \sqrt{5}) times 1/2 times 2 \sqrt{5} =
(4 \sqrt{2}+4 \sqrt{5}) times \sqrt{5} [/tex] =
4 \sqrt{10}+4*5=4 \sqrt{10}+20=80 \sqrt{10}=252.982


























X=(15,8)
Y=(13,4)
BC=4 \sqrt{5}
XY=2 \sqrt{5}
Area=80 \sqrt{10} square unit or 252.982 square units







7 0
3 years ago
Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were 3 mill
abruzzese [7]

Answer:

V' = -0.11552 *V\\= -0.11552(1.8)\\ \\=-0.20794 million per year

Step-by-step explanation:

Given that oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were 3 million barrels of oil in the well; six years later 1,500,000 barrels remain.

i.e. if V stands for volume of oil, then

V' =kV\\dv/V= kdt\\ln V = kt+C\\V = Ae^{kt}

To find A and k

V(0) = A = 3 million

Hence V = 3e^{kt}

V(6) = 1.5

i.e. 1.5 = 3e^{6k}\\ln 1.5 =ln 3 +6k\\k = -0.11552

V(t) = 3e^{-0.11552t}

a) Using the above value of k , we have

V' = -0.11552 *V\\= -0.11552(1.8)\\ \\=-0.20794 million per year.

4 0
3 years ago
Kurt wants to informally prove the converse of the Pythagorean Theorem by producing some evidence that supports it.
Elis [28]

Answer:

A and C

Step-by-step explanation:

I had it on a test

4 0
3 years ago
Hey please I need help with this
saul85 [17]

Answer:

78.5

Step-by-step explanation:

This is because of the formula r^2pi since 5^2=25 and 25x3.14 it equal 78.5

8 0
2 years ago
Parker is testing 2 different types of ant killer in his yard. He purchases Brand A and Brand B from the home improvement store.
NNADVOKAT [17]

Answer:

 

He did not wait as long between each treatment of ant killer.

Step-by-step explanation:

He did one on monday and another on saturday then checked them on sunday

8 0
3 years ago
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